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3 years ago

16. You want to decorate around the top of a jar with ribbon. The length around the jar is

Mathematics

1 answer:

VladimirAG [237]3 years ago

3 0

Answer: A) We need 1 1/2 ft of ribbon

B)$1.60 per foot

C)$2.40 is the total

Step-by-step explanation:

So if the length around the jar is 18 inches and we know that there is 12 inches in a foot, and 3 feet in a yard and $ 4.80 per every 3 feet. These become basis numbers. 18in- 12inch= 6 inch. So now we have 1 1/2 feet of ribbon to cover the circumference of the jar. Now we are left to answer the second question how much does it cost per foot? We can divide 4.80 by 3 to see the total cost of a foot of ribbon. That turns to 1.60 per foot. We divide that by two to cover the 6 inches. And the answer is $2.40 for 1 1/2 feet of ribbon

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A garden has a length of 20 ft. It has a width of 12 ft. What is the area of the garden ?

Crazy boy [7]

Answer:

The answer for your problem is 240

Step-by-step explanation:

A=wl=12·20=240

for this problem all you had to do was multiply

12*20 to get your answer

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3 years ago

20 PTS LOOK AT PIC FOR QUESTION WILL MARK BRAINILEST

hjlf

Answer:

263.25 cm

Step-by-step explanation:

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3 years ago

Jim buys a car for $22,500. He decides to finance through the dealership at 3.5% simple interest for 5.5 years. How much interes

borishaifa [10]

Answer:

4,331.25 in interest

Step-by-step explanation:

22,500.00x3.5%=787.50x5.5=4,331.25

22,500.00+4,331.25=26,831.25 total loan

7 0

3 years ago

If a manufacturer conducted a survey among randomly selected target market households and wanted to be 95% confident that the d

katen-ka-za [31]

Answer:

We need a sample size of least 119

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Sample size needed

At least n, in which n is found when $M = 0.09$

We don't know the proportion, so we use $\pi = 0.5$ , which is when we would need the largest sample size.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.09 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.09\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.09}$

$(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.09})^{2}$

$n = 118.6$

Rounding up

We need a sample size of least 119

6 0

3 years ago

Water freezes at 0° Celsius. The table shows five different temperatures in degrees Celsius. Indicate whether each temperature i

KATRIN_1 [288]

0.5 is above because that .5 of a change is keeping the water from freezing because it is still slightly babouche freezing point.

-13 is below because the number is a negative so is below 0 anyway and is below the freezing point.

100 is above because the number 100 is higher than 0 so it’s above freezing point.

5.5 is above because it is a larger number than the freezing point so the water would not freeze yet at this temperature.

-2.25 is below because it’s a negative number.

I think that’s what you meant not 100% sure but that’s how I would do it :)

8 0

3 years ago