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GaryK [48]
3 years ago
11

Factorise 32 x cube minus 8 y square​

Mathematics
1 answer:
andreev551 [17]3 years ago
6 0

Answer: 8(4x^3-y^2)

Step-by-step explanation:

32x^3-8y^2

8(4x^3-y^2)

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Answer:

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Step-by-step explanation:

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Help please Draw an obtuse angle (labeled BIG) Place a point P inside the angle. Now construct perpendiculars form the point to
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Answer:

The side closest to P is the side that is on the same side of the angle bisector as P.

Step-by-step explanation:

The angle bisector is the line containing all the points equidistant from the sides of the angle. Points on one side of the angle bisector are closer to the angle side that is on that side of the angle bisector.

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The attached diagram shows the angle bisector as a dashed line. A couple of different locations for P are shown (P1 and P2). Apparently, we're concerned here with the distance from P along the perpendicular to each side of the angle. For P2 (on the left side of the angle bisector), it may be clear that the left perpendicular is shorter than the right one. Likewise, for P1, the right perpendicular will be shorter.

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iragen [17]

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Step-by-step explanation:

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During an Apollo moon landing, reflecting panels were placed on the moon. This allowed Earth-based astronomers to shoot laser be
rusak2 [61]

Answer:

The distance between the astronomers and the moon was 7.56*10^{8] meters.

Step-by-step explanation:

We have that the speed is the distance divided by the time, so:

v = \frac{d}{t}

In this problem, we have that:

The reflected laser beam was observed by the astronomers 2.52 s after the laser pulse was sent. This means that t = 2.52.

If the speed of light is 3.00 times 10^8 m/s, what was the distance between the astronomers and the moon?

We have that v = 3*10^{8}m/s.

We have to find d. So:

v = \frac{d}{t}

d = vt

d = 3*10^{8}*2.52

7.56*10^{8]

The distance between the astronomers and the moon was 7.56*10^{8] meters.

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4 years ago
The image of (2, -1) under the transformation T -5, 3 is _____.
LiRa [457]

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\

Step-by-step explanation:

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