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Pavlova-9 [17]
3 years ago
5

You've been asked to order pizza for a

Mathematics
1 answer:
Stolb23 [73]3 years ago
3 0

Answer:

I think the answer is 10

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Find the measure of x and y (NO LINKS OR REPORT)
Alchen [17]

Answer:

y= 35

x=55

Step-by-step explanation:

   

8 0
3 years ago
Solve the following equation for y: 2x-3y=6
Minchanka [31]

2x-3y=6

-y=6

y=-6

<u>Check your Work</u>

-6(2) - 3(-6)=

-12-(-18)=

-12+18=6

5 0
4 years ago
What is the area of this figure? Round to the tenth if necessary.
Julli [10]

Answer:

<h3>b) 850.1 centimeters.</h3>

Step-by-step explanation:

To find the area of this figure, we must first find the areas of the shapes that compose this figure.

This figure is made up of a rectangle and a semicircle.

Remember: To find the area of a semicircle, multiply the radius by itself twice, then multiply the product pi, lastly divide the product by 2.

a=\pi r^2/2

<u>3.14 will be used for pi!</u>

To find the area of a rectangle, multiply the length by the width. The product is the area of the rectangle.

a=lw

Now, let's solve.

The diameter of the semicircle is 32 centimeters.

To find the radius of a semicircle, divide the diameter by 2.

32/2=16

The radius of the semicircle is 16 centimeters.

Now that we have the radius, we can find the area of the semicircle.

\pi 16^2/2=401.92

The area of the semicircle is 401.92 centimeters.

Furthermore, we find the area of the rectangle.

14*32=448.

The area of the circle is 448 centimeters.

Next, we add the areas of both shapes to find the area of this figure.

401.92+448

=849.92

The final step is to round 849.92 to the nearest tenth.

Even though 849.92 to rounded to the nearest tenth is 849.9, there is no answer choice for this. The closest one to this answer is choice 'b.'

I, therefore, believe the area of this figure is 850.1 centimeters.

3 0
3 years ago
Kinsley's age is 7 years less than twice Jacob's age. If Kinsley is 13 years old, how old is Jacob? Choose the answer below that
Ganezh [65]

Answer:

10x2= 20 -7 =13  :answer is 10.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Figure ABCDE has vertices a(-3, 3), b(2, 3), c(5, -2), d(0, -3), and e(-3, -2). Plot the points on your own coordinates grid and
Ilya [14]
<h2>Answer:</h2>

Shown below

<h2>Step-by-step explanation:</h2>

First of all, we have the following points:

a(-3, 3) \\ \\ b(2, 3) \\ \\ c(5, -2) \\ \\ d(0, -3) \\ \\ e(-3, -2)

To plot these points, we need to graph a coordinate grid. Recall that a coordinate grid is composed of two perpendicular lines, that we call the axes and are labeled like number lines. The horizontal axis is called the x-axis while the vertical axis is called the y-axis, and these two axes intersect at a point called the origin. Next, let's plot each point as follows:

<h2>PART 1. Plot the points on your own coordinates grid and connect in alphabetical order. </h2><h2></h2>

Point a:

Let's stand at the origin and then move three units to the left and three units up. The resulting point is shown in the firs figure below.

Point b:

Let's stand at the origin and then move two units to the right and three units up. The resulting point is shown in the firs figure below.

Point c:

Let's stand at the origin and then move five units to the right and two units down. The resulting point is shown in the firs figure below.

Point d:

Let's stand at the origin and then move three units to down. The resulting point is shown in the firs figure below.

Point e:

Let's stand at the origin and then move three units to the left and two units down. The resulting point is shown in the firs figure below.

Next, let's connect connect the points in alphabetical order, so that the line are connected from a to b, from b to c, from c to d, from d to e and from e to a again. So the resulting graph is shown in the second figure. As you can see, this is an irregular pentagon.

<h2>PART 2. Decompose figure ABCDE into rectangles and triangles.</h2>

Every pentagon can be divided up into three triangles. Hence, from the third figure. the triangles are:

ΔABE

ΔBDE

ΔBCD

Since a rectangle is a quadrilateral whose angles are all right angles, then there is no chance to obtain a rectangle from ABCDE. To obtain a rectangle, we'd need other points and this is not what the problem asks.

5 0
3 years ago
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