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DENIUS [597]
3 years ago
13

Which digit in the number 53,941 would be changed to form 58,941? How would the value of 53,941 change?

Mathematics
1 answer:
Luda [366]3 years ago
6 0
The 3 would change to an 8.
It increases the value of the number by 5000 (8-3=5)
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The answer would be 208 if you find the area of each quadrilateral and add them together.
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If the solution to a linear system of equations is x=6 and y= 2 and you graphed the two equations, where would the two lines int
uranmaximum [27]

Answer:

(6,2)

Step-by-step explanation:

Combine them

6 0
3 years ago
Transfer transfer the system of equations by forming a matrix equation.
Anika [276]

Answer:

Step-by-step explanation:

\begin{bmatrix}2 & -3\\ 1 & 2\end{bmatrix}^{-1}\times \begin{bmatrix}2 & -3\\ 1 & 2\end{bmatrix}\times \begin{bmatrix}x\\y \end{bmatrix}=\frac{1}{7} \begin{bmatrix}2  & 3 \\ -1 & 2\end{bmatrix}\times \begin{bmatrix}19\\ -1\end{bmatrix}  

Since, \begin{bmatrix}2 & -3\\ 1 & 2\end{bmatrix}^{-1}=\frac{1}{7}\begin{bmatrix}2 & 3\\ -1 & 2\end{bmatrix}

And A^{-1}A=I

\begin{bmatrix}x\\y \end{bmatrix}=\frac{1}{7}\begin{bmatrix}2 & 3\\ -1 & 2\end{bmatrix}\times \begin{bmatrix}19\\-1 \end{bmatrix}

\begin{bmatrix}x\\y \end{bmatrix}=\frac{1}{7}\begin{bmatrix}35\\ -21\end{bmatrix}

\begin{bmatrix}x\\y \end{bmatrix}=\begin{bmatrix}5\\ -3\end{bmatrix}                

Therefore, x = 5 and y = -3 will be the value of variables.

3 0
3 years ago
.After a dilation with a center of (0, 0), a point was mapped as (1, 4) → (4, y). A student determined y to be 16. Evaluate the
BaLLatris [955]
The right answer for the question that is being asked and shown above is that: "C. The student incorrectly multiplied by the scale factor instead of adding it." .After a dilation with a center of (0, 0), a point was mapped as (1, 4) → (4, y). A student determined y to be 16.

The right answer for the question that is being asked and shown above is that: "C. <span>only 1."</span>
8 0
3 years ago
For the right triangle shown, the lengths of two sides are given. Find the third side. Leave your answer in simplified, radical
sleet_krkn [62]

Answer: c=4\sqrt{2}

Step-by-step explanation:

For this exercise you need to apply the Pythagorean Theorem. This is:

h^2=l^2+m^2

Where "h" is the hypotenuse of the Right triangle and "l" and "m" are the legs.

In this case, you can identify that:

h=c\\\\l=a=4\\\\m=b=4

Knowing these values, you can substitute them into  h^2=l^2+m^2:

c^2=4^2+4^2

Now you must solve for "c":

c=\sqrt{4^2+4^2}

Evaluating, you get:

c=\sqrt{16+16}\\\\c=\sqrt{32}

To simplify the result:

- Descompose 32 into its prime factors:

32=2*2*2*2*2=2^5

- By the Product of powers property, you know that:

2^5=2^4*2

- Make the substitution:

c=\sqrt{2^4*2}

- Finally, knowing that \sqrt[n]{a^n}=a, you get:

c=2^2\sqrt{2}\\\\c=4\sqrt{2}

6 0
3 years ago
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