Lim (
c{x^2-2x-3}{x-3}" align="absmiddle" class="latex-formula">) as x tends to 3
2 answers:
The roots of the nominator are:
Which means that the nominator can be written as:
Thus we compute the limit as shown below:
Answer:
4
Step-by-step explanation:
If you replace x with 3 in the expression you will get an indefenite form (0/0)
So there two methods.
The easiest one is applying The hospital rule
Derivate the expression firsr but separatly.
● (x^2 -2x -3)' = 2x - 2
● (x-3)' = 1
When x tends to 3
Lim(x^2-2x-3/x-3) = lim (2x-2/1) = 6-2 = 4
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