4 years ago

I need help with dis

Mathematics

2 answers:

neonofarm [45]4 years ago

8 0

Answer:C is supposed to be in eight and six/ 8 and 10 should be 40

Step-by-step explanation:

Neko [114]4 years ago

8 0

Answer:

1=8, 2=24, 3=40

Step-by-step explanation:

You might be interested in

A camera rental company charges a fixed amount plus a fee based on the number of days for which the camera is rented. The graph

bija089 [108]

Given:
x y
0 40
4 120

y = fixed amount + v(x)
y = 40 + v(0)
y = 40

y = 40 + v(x)
120 = 40 + v(4)
120 - 40 = v(4)
80 = v(4)
80/4 = v
20 = v

y = 40 + 20x

The fixed amount charged is 40.

The variable amount is 20 per day.

7 0

3 years ago

Read 2 more answers

Convert to a mixed number. - 10/3

Artist 52 [7]

Answer:

-10/3

Step-by-step explanation:

because its a proper fraction and it can't be a mixed number

8 0

3 years ago

color copies cost 10 cents per copy and white copies cost 5 cents per copy. sandy made 400 copies, some of which were colored an

muminat

The answer is 80 copies

7 0

3 years ago

SOME ONE HELP PLEASE

Lapatulllka [165]

The answer is 5 i believe

4 0

3 years ago

Give a third degree polynomial that has zeros of 13, 5i, and −5i, and has a value of −680 when x=3. Write the polynomial in stan

Vikki [24]

Answer:

$\dfrac{17x^3-221x^2+425x-5525}{9}\\$

Step-by-step explanation:

hello

we need to find something like, a being real

$a(x-13)(x-5i)(x+5i)$

with a so that

$a(3-13)(3-5i)(3+5i)=-680\\\\a(-10)(3^2-(5i)^2)= -10(9+25)a=-360a=-680\\ a = \dfrac{680}{360}=\dfrac{17*40}{9*40}=\dfrac{17}{9}$

so the third degree polynomial that we are looking for is

$\dfrac{17}{9}(x-13)(x-5i)(x+5i)\\=\dfrac{17}{9}(x-13)(x^2+25)\\\\=\dfrac{17}{9}(x^3+25x-13x^2-13*25)\\\\\\=\dfrac{17}{9}(x^3-13x^2+25x-325)\\\\\\\\=\dfrac{17}{9}x^3-\dfrac{17*13}{9}x^2+\dfrac{17*25}{9}x-\dfrac{17*325}{9}\\=\dfrac{17}{9}x^3-\dfrac{221}{9}x^2+\dfrac{425}{9}x-\dfrac{5525}{9}\\$

hope this helps

3 0

4 years ago