It depends on how b approaches 0
If b is positive and gets closer to zero, then we say b is approaching 0 from the right, or from the positive side. Let's say a = 1. The equation a/b turns into 1/b. Looking at a table of values, 1/b will steadily increase without bound as positive b values get closer to 0.
On the other side, if b is negative and gets closer to zero, then 1/b will be negative and those negative values will decrease without bound. So 1/b approaches negative infinity if we approach 0 on the left (or negative) side.
The graph of y = 1/x shows this. See the diagram below. Note the vertical asymptote at x = 0. The portion to the right of it has the curve go upward to positive infinity as x approaches 0. The curve to the left goes down to negative infinity as x approaches 0.
If y=15 then x=45 because 45 minus 15 is 30
Hope this helps :))
There are approximately 261 weekdays in a year
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Answer:
- zeros: t = 1, t = -1/2
- no: the domain of the function is t ≥ 0
- 8 feet
Step-by-step explanation:
The zeros are the values of t that make the factors zero.
1 -t = 0 ⇒ t = 1
8 +16t = 0 ⇒ t = -8/16 = -1/2
The equation is used to model height after the ball is thrown. We don't expect it to be a good model before the ball is thrown (t < 0), so the zero in that region is extraneous.
Only the positive zero is in the function's domain, so that is the only one that is meaningful.
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When t = 0 (at the time the ball is thrown), the function value is ...
h(0) = (1 -0)(8 +0) = 8
The ball is thrown from a height of 8 feet.
I’m a complete parallelogram