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solong [7]
3 years ago
10

What is an equation of the line that is perpendicular to y-4=2(x-6) and passes through the point (-3,-5)

Mathematics
2 answers:
solong [7]3 years ago
7 0

Answer:

y+5=-\frac{1}{2}(x+3)

Step-by-step explanation:

The given equation is

y-4=2(x-6)

This equation is in the point-slope form, y-y_1=m(x-x_1), where m=2 is the slope of this line.

The line that is perpendicular to this line has slope -\frac{1}{2}

If this line that is perpendicular to the given line passes through (-3,-5), then it will have equation;

y--5=-\frac{1}{2}(x--3)

y+5=-\frac{1}{2}(x+3) in point-slope form

krok68 [10]3 years ago
3 0

Answer:

y+5 = -1/2(x + 3)

Step-by-step explanation:

Perpendicular lines have negative reciprocal slopes. The slope of the line

y - 4 = 2(x - 6) is 2. Its negative reciprocal slope is -1/2.

Using m = -1/2 and the point (-3,-5) in the point slope form.

y --5 = -1/2(x--3)

y+5 = -1/2(x + 3)

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