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KATRIN_1 [288]
3 years ago
10

A girl performs 300 J of work lifting a weight to a height of 2 m. How much

Physics
2 answers:
Ulleksa [173]3 years ago
5 0

A lift requires 300J to complete 2m of vertical distance aka height. We must find force exerted by a girl on the object that was lifted 2m vertically.

So we divide.

F=\dfrac{W}{h}=\dfrac{300\mathrm{J}}{2\mathrm{m}}=150\mathrm{N}

Hope this helps.

Ivanshal [37]3 years ago
3 0

<u>Answer:</u> The force applied by the girl is 150 N

<u>Explanation:</u>

Work is defined as the force that is causing the movement or displacement of an object.

Mathematically,

W=F\times d

where,

W = work done by the girl = 300 J

F = Force applied by the girl = ?

d = displacement = 2 m

Putting values in above equation, we get:

300J=F\times 2m\\\\F=\frac{300J}{2m}=150N

Hence, the force applied by the girl is 150 N

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a load of 800 newton is lifted by an effort of 200 Newton. if the load is placed at a distance of 10 cm from the fulcrum. what w
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40 cm

Explanation:

We are given that

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Using the formula

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A cable is 100-m long and has a cross-sectional area of 1.0 mm2. A 1000-N force is applied to stretch the cable. Young's modulus
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