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KATRIN_1 [288]
3 years ago
10

A girl performs 300 J of work lifting a weight to a height of 2 m. How much

Physics
2 answers:
Ulleksa [173]3 years ago
5 0

A lift requires 300J to complete 2m of vertical distance aka height. We must find force exerted by a girl on the object that was lifted 2m vertically.

So we divide.

F=\dfrac{W}{h}=\dfrac{300\mathrm{J}}{2\mathrm{m}}=150\mathrm{N}

Hope this helps.

Ivanshal [37]3 years ago
3 0

<u>Answer:</u> The force applied by the girl is 150 N

<u>Explanation:</u>

Work is defined as the force that is causing the movement or displacement of an object.

Mathematically,

W=F\times d

where,

W = work done by the girl = 300 J

F = Force applied by the girl = ?

d = displacement = 2 m

Putting values in above equation, we get:

300J=F\times 2m\\\\F=\frac{300J}{2m}=150N

Hence, the force applied by the girl is 150 N

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Answer:

Fe= 2579.68 P

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Explanation:

Look at the attached graphic

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Fnx= -2341.87 P, then, Fex= +2341.87 P

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