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Mnenie [13.5K]
3 years ago
5

What does y equal y-16-3y=0

Mathematics
1 answer:
Afina-wow [57]3 years ago
7 0

Answer:

y = - 8

Step-by-step explanation:

y - 16 - 3y = 0

Group like terms

y - 3y - 16 = 0

Add similar elements: y - 3y = - 2y

- 2y - 16 = 0

Add 16 to both sides

- 2y - 16 + 16 = 0 + 16

Simplify

- 2y = 16

Divide both sides by - 2

\frac{-2y}{-2} = \frac{16}{-2}

Simplify \frac{-2y}{-2}: y

\frac{-2y}{-2}

Apply the fraction rule: \frac{-a}{-b}  = \frac{a}{b}

= \frac{2y}{2}

Divide the numbers: \frac{2}{2}  = 1

= y

Simplify \frac{16}{-2}: - 8

\frac{16}{-2}

Apply the fraction rule: \frac{-a}{-b}  = \frac{a}{b}

-\frac{16}{2}

Divide the numbers: \frac{16}{2} = 8

= - 8

y = - 8

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Answer:

The correct option is D) f(x) = x^3 + 2x^2 - 2x - 4 .

Step-by-step explanation:

Consider the provided cubic function.

We need to find the equation having zeros: Square root of two, negative Square root of two, and -2.

A "zero" of a given function is an input value that produces an output of 0.

Substitute the value of zeros in the provided options to check.

Substitute x=-2 in f(x) = x^3 + 2x^2 - 2x + 4 .

f(x) = x^3 + 2x^2 - 2x + 4\\f(x) = (-2)^3 + 2(-2)^2 - 2(-2) + 4\\f(x) =-8 + 2(4)+4 + 4\\f(x) =8

Therefore, the option is incorrect.

Substitute x=-2 in f(x) = x^3 + 2x^2 + 2x - 4 .

f(x) = x^3 + 2x^2 + 2x - 4\\f(x) = (-2)^3 + 2(-2)^2 + 2(-2) - 4\\f(x) =-8+2(4)-4-4\\f(x) =-8

Therefore, the option is incorrect.

Substitute x=-2 in f(x) = x^3 - 2x^2 - 2x - 4 .

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Therefore, the option is incorrect.

Substitute x=-2 in f(x) = x^3 + 2x^2 - 2x - 4 .

f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-2)^3+2(-2)^2 - 2(-2) - 4\\f(x) =-8+8+4-4\\f(x) =0

Now check for other roots as well.

Substitute x=√2 in f(x) = x^3 + 2x^2 - 2x - 4 .

f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (\sqrt{2})^3+2(\sqrt{2})^2 - 2(\sqrt{2}) - 4\\f(x) =2\sqrt{2}+4-2\sqrt{2}-4\\f(x) =0

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Therefore, the option is correct.

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