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slega [8]
3 years ago
11

When a polynomial p(x)is divided by x-1, the remainder is 5 and when p(x) is divided by x-2, the remainder is 7. Find the remain

der when the same expression is divided by (x-1)(x-2)
ANSWER FAST
Mathematics
1 answer:
andrew11 [14]3 years ago
4 0

Answer:

h6=64

Step-by-step explanation:

the answer is this h6=762

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Dieikenfjdj dodkfkdkd dkdkfkdndd disk djdkd
7 0
3 years ago
How do you know 3 ÷180 is smaller than 1​
Diano4ka-milaya [45]

Answer:

Because 180 is bigger than 3 and your trying to divide 180 into 3. Which isn't gonna come out an even number. 0.01666666666 is a lot smaller than 3.

Step-by-step explanation:

Hope this helped!!!

7 0
3 years ago
Read 2 more answers
54.85 rounded to the nearest 1/10th percent
Iteru [2.4K]

Answer:

54.9

Step-by-step explanation:

You always round up if its 0.5 or anything .5

54.58 broken down:

The 5 is the Tens place

The 4 is the Ones place

The 8 is the Tenth place (what the question is asking for)

The 5 is the Hundredths place.

:)  Hope this helps! Please mark brainliest! :)

8 0
3 years ago
A couple plans to have children until they get a​ girl, but they agree they will not have more than three​ children, even if all
barxatty [35]

Answer:

a)Let X be number of children

X=1,2,3

P(X=1)= 0.47

P(X=2) = 0.2491

P(X=3) = 0.942923

b) 3.7970

c) 1.6232

Step-by-step explanation:

The complete question is:

A couple plans to have children until they get a​ girl, but they agree they will not have more than three​ children, even if all are boys. Assume that the probability of having a girl is 47.00​%. ​

a) Create a probability model for the number of children​ they'll have.

X=1,2,3

​P(X=1)=??

P(X=2)= ??

P(X=30=???

​(Round to four decimal places as​ needed

​b) Find the expected number of children.

E(X)= ???

​c) Find the expected number of boys​ they'll have.

Expected number of boys= ???

Solution:

Probability of a girl= 0.47

Probability of a boy= 0.53

a) P(X=1)= 0.47

P(X=2) = 0.47× 0.53= 0.2491

P(X=3)= 0.47× 0.53× 0.53 + 0.53× 0.53× 0.53

             = 0.942923

b) E(number of children)= 1× P(X=1) + 2 ×P(X=2) + 3 × (PX=3)

                                       = 3.796969

c) Y: number of boys

P(Y=1)= 0.53×0.47= 0.2491

P(Y=2) = 0.53×0.53×0.47=0.46375

P(Y=3)= 0.53× 0.53× 0.53= 0.148875

E(Y)= P(Y=1)×1 + P(Y=2)×2 + P(Y=3)×3

       = 0.148875×3 +0.46375×2+0.2491 ×1

      = 1.6232

5 0
3 years ago
Solve by substitution 2.5x-3y=-3 3.25x-y=-14
zhuklara [117]
Hello Complimentmady1, the first question, answer: <span>x=<span><span>1.2y</span>−1.2</span></span><span> second question, </span>answer:<span /><span> x=<span><span>0.307692y</span>−4.307692.</span></span>


4 0
3 years ago
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