The answer is C. Maybe im not sure
No generations or hybrid would form before meselson and stahl would have observed evidence of a band in the cscl gradient.
The conservative model predicts that, following a single replication, half of the newly formed DNA double helices will be made entirely of the original, or old, DNA, and the other half will be entirely new. Then, each double helix would be completely replicated during the second round of replication. After that, 25% of the double helices would be all new, and 25% would be entirely old. Thus, the fraction of entirely new DNA double helices would increase with each succeeding round of replication, but the total number of completely unique DNA double helices would remain constant. Therefore, no hybrid DNA molecule containing 14N and 15N is replicated in the conservative model.
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Answer:
This question is incomplete
Explanation:
This question is incomplete because of the absence of the chart referred to in the question. However, what appears to be the case is that the three nitrogenous bases represent codons (and the missing chart is the codon chart). The mutation that has the potential to cause more damage will be the one that would change the amino acid formed from the codon change.
A. CAU to CAC: The codons CAU and CAC both form the amino acid histidine and thus is not expected to cause a major damage.
B. UGU to UGC: The codons UGU and UGC both form the amino acid cysteine and thus is not expected to cause a major damage.
C. UCU to UUU: <u>Codon UCU forms the amino acid serine while the codon UUU forms the amino acid phenylalanine</u>. Thus, this eventual change in the amino acid formed has the potential to cause a major damage and thus option C is the correct option.
NOTE that a codon is a sequence of three DNA/RNA nucleotides that corresponds to a single amino acid.