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ikadub [295]
3 years ago
6

Solve the equation for a. 55a – 44a = 11

Mathematics
2 answers:
Yanka [14]3 years ago
7 0
55a-44a=11  combine like terms on the left side

11a=11  divide both sides by 11

a=1
nignag [31]3 years ago
7 0
55a - 44a = 11
11a = 11
a = 1
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What does a graph look like with the points plotted (1,-6), (8,-9)
vitfil [10]
I need help on this to
8 0
3 years ago
Use appropriate algebra and theorem 7. 2. 1 to find the given inverse laplace transform. (write your answer as a function of t.
ollegr [7]

The given function s/(s^2 +3s -4) is proved with the help of inverse Laplace theorem.

According to the statement

we have to find the inverse of the Laplace theorem with the help pf the given theorem in the statement.

So, For this purpose, we know that the

Laplace transformation is a transformation of a function f(x) into the function g(t) that is useful especially in reducing the solution of an ordinary linear differential equation with constant coefficients to the solution of a polynomial equation.

Now, We assume you want to find the inverse transform of s/(s^2 +3s -4).

This can be written in partial fraction form as

\frac{(4/5)}{(s+4)} + \frac{(1/5)}{(s-1)}

which can be found in a table of transforms to be the transform of

\frac{4}{5} e^{-4t} + \frac{1}{5} e^t

There are a number of ways to determine the partial fractions. They all start with factoring the denominator.

s^2 +3x -4 = (s+4)(s-1)

After that, you can postulate the final form and determine the values of the coefficients that make it so.

For example:

\frac{A}{(s+4)}  + \frac{B}{s-1}  = (A+B)s + \frac{(4B-A)}{(s^2 +3x -4)}

This gives rise to two equations:

(A+B) = 1

(4B-A) = 0.

So, The given function s/(s^2 +3s -4) is proved with the help of inverse Laplace theorem.

Disclaimer: This question was incomplete. Please find the full content below.

Question:

Use appropriate algebra and theorem 7.2.1 to find the given inverse laplace transform. (write your answer as a function of t.) ℒ−1 s s2 + 3s − 4.

Learn more about Laplace here

brainly.com/question/11630973

#SPJ4

3 0
2 years ago
Find the area of the trapezoid below.
Pani-rosa [81]

Answer: 54 cm²

Step-by-step explanation: In this problem, we're asked to find the area of the trapezoid shown. A trapezoid is a quadrilateral with one pair of parallel sides.

The formula for the area of a trapezoid is shown below.

Area =\frac{1}{2} (^{b} 1 + ^{b}2)h

The <em>b's</em> represent the bases which are the parallel sides and <em>h</em> is the height.

So in the trapezoid shown, the bases are 6 cm and 12 cm and the height is 6 cm. Plugging this information into the formula, we have \frac{1}{2} (6 cm +12cm)(6 cm).

Next, the order of operations tell us that we must simplify inside the parentheses first. 6 cm + 12 cm is 18 cm and we have \frac{1}{2}(18 cm)(6 cm).

\frac{1}{2} (18 cm) is 9 cm and we have 9 cm · 6 cm of 54 cm²

So the area of the trapezoid shown is 54 cm².

7 0
3 years ago
(Algebra 2 Conics):
olchik [2.2K]

\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ 4p(y- k)=(x- h)^2 \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ -\cfrac{1}{4}(y+2)^2=x-7\implies -\cfrac{1}{4}[y-(-2)]^2=x-7 \\[2em] [y-(-2)]^2=-4(x-7)\implies [y-(\stackrel{k}{-2})]^2=4(\stackrel{p}{-1})(x-\stackrel{h}{7})


so h = 7, k = -2, meaning the vertex is at (7, -2).

the squared variable is the "y", meaning is a horizontal parabola.

the "p" distance is negative, for a horizontal parabola that means, it's opening towards the left-hand-side.

we know the focus and directrix are "p" units away from the vertex, and we know the parabola is opening horizontally towards the left-hand-side.

the focus is towards it opens 1 unit away, at (6, -2).

the directrix is on the opposite direction, 1 unit away, at (8, -2), namely x = 8.

8 0
3 years ago
The numerical value of sin²5° + sin²10° + sin²15° +... sin²85° + sin²90° is equal a) 17/2 b) 19/2 c) 15/2 d) 13/2​
Vikki [24]

Answer: b)~\Large\boxed{\frac{19}{2} }

Step-by-step explanation:

<h3>Given expression</h3>

sin²5° + sin²10° + sin²15° +... sin²85° + sin²90°

<h3>Concept:</h3>

sin²x + cos²x = 1

sin(x) = cos (90 - x)

<u />

<u>There are in total these terms:</u>

5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90

<u>In total, there are 18 terms, and the first one matches with the second to the last one:</u>

5 -- 85

10 -- 80

.

.

.

40 -- 50

<u />

<u>There are 2 terms left over:</u>

sin²45 and sin²90

<h3>Convert the first half of the sine terms (sin²5 - sin²40) to the cosine terms</h3>

sin²5 = cos² (90 - 5) = cos²85

sin²10 = cos² (90 - 10) = cos²80

.

.

.

sin²40 = cos² (90 - 40) = cos²50

<h3>Simplify the 16 grouped terms </h3>

<em>i.e. sin²85 and cos²85</em>

Using the concept of sin²x + cos²x = 1

sin²85 + cos²85 = 1

sin²80 + cos²80 = 1

.

.

.

sin²50 + cos²50 = 1

Total = (16/2) × 1 = 8 × 1 = 8

<h3>Evaluate the 2 terms that are left over</h3>

sin²45 = (sin45) (sin45) = (√2 / 2) (√2 / 2) = 1/2

sin²90 = (sin90) (sin 90) = (1) (1) = 1

<h3>Add all the terms together</h3>

8+\dfrac{1}{2} +1=\Large\boxed{\frac{19}{2} }

Hope this helps!! :)

Please let me know if you have any questions

8 0
1 year ago
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