Answer:
A set of prime number between 5 and 15.
Listing method:{ 7,11,13}
Set builder method:{X:X is a set of prime number between 5 and 15}
In listing method,the elements are listed inside the brackets.Listing method are also called rooster method.
In set builder method,the elements are represented by a variable stating their common properties.Set builder method are also called rule method.
Hope this helps...
Good luck on your assignment..
I believe the answer is not enough information <span />
- the hundreds digit value is 4.
- The tens digit value is 4
the relation between the values of these two digits is an equality relation.
<h3 /><h3>How to compare the hundreds value and the tens value?</h3>
In a 3 digit number digit, each place value has a name. The hundreds digit value is the digit in the third place (counting from the right) and the tens digit value is the digit in the second place (finally, the unit digit value is the first digit, but this does not matter for this question).
In this case, the three-digit number is:
440
- Then the hundreds digit value is 4.
- The tens digit value is 4
So both numbers are 4.
Now, we can see that both digits are the same digit, so the relation between the values of these two digits is an equality relation:
4 = 4
If you want to learn more about place values:
brainly.com/question/12386995
#SPJ1
Answer:
(x - 10)² + y² = 29
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
Here (h, k) = (10, 0), thus
(x - 10)² + (y - 0)² = r²
The radius is the distance from the centre to a point on the circle
Calculate r using the distance formula
r = √ (x₂ - x₁ )² + (y₂ - y₁ )²
with (x₁, y₁ ) = (10, 0) and (x₂, y₂ ) = (5, 2)
r = 
= 
= 
= 
Thus
(x - 10)² + (y - 0)² = ( )², that is
(x - 10)² + y² = 29 ← equation of circle
