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3 years ago

If x=-2 calculate the value of x2 plus 2x

Mathematics

1 answer:

AfilCa [17]3 years ago

6 0

I think it's -8 (-2)(2) + (2)(-2)
-4+-4=-8

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Anettt [7]

Answer:

2 im pretty sure

Step-by-step explanation:

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3 years ago

If the 13th and 38th terms of an arithmetic sequence are -53 and -128,

love history [14]

9514 1404 393

Answer:

-2018

Step-by-step explanation:

The n-th term is ...

an = a1 +d(n -1)

So, the given terms are ...

-53 = a1 +12d

-128 = a1 +37d

Subtracting the first from the second gives ...

(a1 +37d) -(a1 +12d) = (-128) -(-53)

25d = -75

d = -3

The 668th term will be ...

a668 = a1 +d(668 -1) = a1 +667d = (a1 +37d) +630d

a668 = -128 +630(-3) = -128 -1890 . . . . substitute for a38

a668 = -2018

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3 years ago

A circle has a diameter of 10 millimeters. What is the area of the circle?

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3 years ago

What is 12% of $19.50?

Blababa [14]

The answer would be c.2.34

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3 years ago

Read 2 more answers

(2/3q – 3/4) and (–1/6q – r) What is the coefficient of q in the sum of these two expressions?

oee [108]

Answer:

The co-efficient of q in sum of the given expression is 2

Step-by-step explanation:

Given expressions are $\frac {2}{3q}-\frac {3}{4}$ and $\frac{-1}{6q}-r$

Now sum the given expression

$\frac {2}{3q}-\frac {3}{4} + \frac{-1}{6q} -r = \frac{4-1}{6q} -\frac{3}{4} -r$

$\frac {2}{3q}-\frac {3}{4} + \frac{-1}{6q} -r = \frac{3}{6q} -\frac{3}{4} -r$

$\frac {2}{3q}-\frac {3}{4} + \frac{-1}{6q}-r =\frac{1}{2q} - \frac{3}{4} -r$

Here the co-efficient q is 2 (since $\frac{1}{q} = \frac{1}{2}$ )

3 0

4 years ago