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Ksju [112]
3 years ago
8

Question 18 of 112

Mathematics
1 answer:
forsale [732]3 years ago
7 0

Answer:

23820$

Step-by-step explanation:

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On a diagram of the arena, the car park's length is 15 cm. The scale is 1:100.
faltersainse [42]

If a diagram has a scale of 1:100, that means that the real thing is 100 times larger. To find how long the real thing is, that means that we need to multiply the length on the diagram by 100. 100 * 15 is 1500. But, that is 1,500 cm. To convert it into meters, we need to divide by 100. That's because there's 100 centimeters in every meter. 1500/100 is 15, which means that the actual length of the car park is 15 meters.

8 0
3 years ago
A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D.
yKpoI14uk [10]

The correct statement is:

  • There are four ways to choose the committee.
  • There are three ways to form the committee if person D must be on it.
  • If persons B and C must be on the committee, there are two ways to form the committee.

It is given that:

A membership committee of three is formed from four eligible members.

1) There are four ways to choose the committee.

This statement is true.

Since we have to choose 3 members out of the 4 members so we can use the method of combination.

2) There are three ways to form the committee if person D must be on it.

This statement is also true.

Since D has to be in the committee, this means we have to choose 2 more people out of the three people to form the committee.

3) If seven members are eligible next year, then there will be fewer combinations.

This statement is wrong.

Since we have to choose 3 members out of 7 members so the number of possible combinations will be:

There are 35 combinations possible.

4) If persons B and C must be on the committee, there are two ways to form the committee.

If B and C have to be in the committee then we have to choose just one person out of the two people left.

Hence, the statement is true.

5) If persons A and C must be on the committee, then there is only one way to form the committee.

If A and C have to be on the committee then as in the last option we have to choose any one of the two-person left.

So possible number of ways is 2.

Hence, the statement is false.

Learn more about committee here: brainly.com/question/425830

#SPJ4

<em>Your question is incomplete. Please read below to find the missing content.</em>

<em />

A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D. The possible outcomes include S = {ABC, ABD, ACD, BCD}.

Which statements about the situation are true? Check all that apply.

There are four ways to choose the committee.

There are three ways to form the committee if person D must be on it.

If seven members are eligible next year, then there will be fewer combinations.

If persons B and C must be on the committee, there are two ways to form the committee.

If persons A and C must be on the committee, then there is only one way to form the committee.

8 0
1 year ago
Plsssssss help -1 3/10 + 2/5
vitfil [10]

Answer:

Step-by-step explanation:

-9/10 or -0.9

8 0
3 years ago
Using 6 as a denominator, what fraction completes the following equation: 1 − 1/3 = ? a. 3/6 c. 5/6 b. 4/6 d. 2/6
nika2105 [10]
C
because of explain
6 0
3 years ago
The graphs below have the same shape. What is the equation of the red<br> graph?
user100 [1]

Step-by-step explanation:

If they have the same shape, the red graph is a translation of the blue, which is given to be y=x^2.

Since the red graph stays on the y axis at two units above the blue (y=x^2) curve, therefore the red curve is given by y=x^2+2.

6 0
2 years ago
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