Answer:
Equation 1 would be: 3a+2C
Equation 2 would be: 5a+3C
Step-by-step explanation:
Answer:
in 6 years
Step-by-step explanation:
Using t=10 to represent today, we can write the exponential growth function as ...
p(t) = 200(550/200)^(t/10)
Then we can set p(t) = 1000 and solve for t:
1000 = 200(11/4)^(t/10) . . . . simplifying the growth factor
1000/200 = (11/4)^(t/10) . . . . divide by 200
log(5) = (t/10)log(11/4) . . . . . . take logs
t = 10·log(5)/log(11/4) ≈ 15.91
That is, about 16 years from 10 years ago, the population will reach 1000.
The population will reach 1000 in about 6 years.
By using differential equations' concept, we get that there is no sugar in the beginning.
<h3>What is a differential equation?</h3>
A differential equation is an equation that connects the derivatives of one or more unknown functions.
Given:
Pure water = 2840 litres
sugar = 0.01kg per liter
Rate of sugar entering the tank = 4liter/min
New solution drains out at the rate = 4 litre/min
To find: sugar in the beginning.
Finding:
(a) In the beginning, the tank contains only pure water and no solution of water with sugar.
Hence, the sugar is null for t = 0.
To learn more about differential equations, refer to the link: brainly.com/question/1164377
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In a system of equations with two variables, you generally need two equations to find a unique solution, and this system is no exception. One example of a solution to this problem is (1, 2), but (3, 9) and (5, 16) also work, and there are actually infinitely many solutions to this single equation.