Question

Write an equation of the line that passes through the given points. (0,−3),(3,3)

Answer 1

(0,-3)(3,3)
slope = (3 - (-3) / (3 - 0) = (3 + 3) / 3 = 6/3 = 2

y = mx + b
slope(m) = 2
use either of ur points....(0,-3)...x = 0 and y = -3
now sub and find b, the y int
-3 = 2(0) + b
-3 = b

so ur equation is : y = 2x - 3

Answer 2

Nice, we got a y intercept

y=mx+b
m=slope
b=y intercept


the slope between the point (x1,y1) and (x2,y2) is
(y1-y2)/(x1-x2)
given
(0,-3) and (3,3)
slope=(-3-3)/(0-3)=-6/-3=2

the y intercept is where x=0
given (0,-3)
(x,y)
the y intercept is -3


slope is 2=m
y intercept is -3=b

y=2x-3 is answer