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wel
3 years ago
15

The length and width of each rectangle is given. Which rectangle will not have the same perimeter as the others? l = 12, w = 12

l = 14, w = 9 l = 8, w = 16 l = 13, w = 11
Mathematics
1 answer:
Virty [35]3 years ago
7 0

Rectangle 2 (<em>l</em> = 14, <em>w</em> = 9) will not have same perimeter as the others

Solution:

Given length and width of the 4 rectangles.

Rectangle 1: length = 12 units, width = 12 units

Perimeter of the rectangle = 2(length + breadth)

Perimeter of rectangle 1 = 2(12 + 12)

                                        = 2 × 24

                                        = 48 units

Perimeter of rectangle 1 = 48 units

Rectangle 2: length = 14 units, width = 9 units

Perimeter of rectangle 2 = 2(14 + 9)

                                        = 2 × 23

                                        = 46 units

Perimeter of rectangle 2 = 46 units

Rectangle 3: length = 8 units, width = 16 units

Perimeter of rectangle 3 = 2(8 + 16)

                                        = 2 × 24

                                        = 48 units

Perimeter of rectangle 3 = 48 units

Rectangle 4: length = 13 units, width = 11 units

Perimeter of rectangle 4 = 2(13 + 11)

                                        = 2 × 24

                                        = 48 units

Perimeter of rectangle 4 = 48 units

Hence rectangle 2 (<em>l</em> = 14, <em>w</em> = 9) will not have same perimeter as the others.

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