Rectangle 2 (<em>l</em> = 14, <em>w</em> = 9) will not have same perimeter as the others
Solution:
Given length and width of the 4 rectangles.
Rectangle 1: length = 12 units, width = 12 units
Perimeter of the rectangle = 2(length + breadth)
Perimeter of rectangle 1 = 2(12 + 12)
= 2 × 24
= 48 units
Perimeter of rectangle 1 = 48 units
Rectangle 2: length = 14 units, width = 9 units
Perimeter of rectangle 2 = 2(14 + 9)
= 2 × 23
= 46 units
Perimeter of rectangle 2 = 46 units
Rectangle 3: length = 8 units, width = 16 units
Perimeter of rectangle 3 = 2(8 + 16)
= 2 × 24
= 48 units
Perimeter of rectangle 3 = 48 units
Rectangle 4: length = 13 units, width = 11 units
Perimeter of rectangle 4 = 2(13 + 11)
= 2 × 24
= 48 units
Perimeter of rectangle 4 = 48 units
Hence rectangle 2 (<em>l</em> = 14, <em>w</em> = 9) will not have same perimeter as the others.
