3 years ago

Is 6/92 in simplest form?

Mathematics

1 answer:

lorasvet [3.4K]3 years ago

8 0

Answer is 3/46 good luck

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igomit [66]

Answer:

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Step-by-step explanation:

Tell me if I'm wrong it might just be B and C.

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3 years ago

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3 years ago

If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe

Natalka [10]

Answer:

They encircle the planet $3.76\times 10^{11}$ times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is $6.022\times 10^{23}$

Thus, the number of dust particles is:

$2.5\times 6.022\times 10^{23}=15.055\times 10^{23}$

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: $10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m$

If we line up the particles the distance they could cover is:

$15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}$

Circumference in meters:

$40,076km\times \frac{1000m}{1km}=40,076,000 m$

Therefore,

$\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}$

Hence, they encircle the planet $3.76\times 10^{11}$ times.

8 0

3 years ago

Please, someone, help me

qwelly [4]

Answer:

282.7 in³

Step-by-step explanation:

The solid is a cylinder

Volume of the cylinder = πr²h

Where,

radius (r) = 3 in.

height (h) = 10 in

Volume = π*3²*10

= π*9*10

= π*90

= 282.743339 ≈ 282.7 in³ (nearest tenth)

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3 years ago

Interest earned: $84<br> Principal: 600<br> Interest rate: 7%<br> Time: ?

olga2289 [7]

If it simple interest it’s 2 years

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3 years ago

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