Question

7. Assume you are dealing with a vertical walled reservoir having a surface area of 650,000 mwith an inflow of 0.5 m/s. How many hours will it take to raise the reservoir by 35 cm? (3 marks)

Answer 1

Answer:

So reservoir will take 455000 sec to raise 35 cm

Explanation:

We have given surface area of the reservoir = 650000 $m^2$

Rate of flow = 0.5 m/sec

Height through which reservoir is raise = 35 cm = 0.35 m

So volume $\Delta V=surface\ area\times height=650000\times 0.35=227500m^3$

We have to calculate the time

Time is given by $t=\frac{\Delta V}{rate\ pf\ flow}=\frac{227500}{0.5}=455000sec$