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Sloan [31]
3 years ago
6

Factor 3M^2+11MN+6N^2

Mathematics
1 answer:
antoniya [11.8K]3 years ago
8 0
3M^2 + 11MN + 6N^2 = 3M^2 + 2MN + 9MN + 6N^2

= M(3M + 2N) + 3N(3M + 2N) = (3M + 2N)(M + 3N)

Answer: 3M^2 + 11MN + 6N^2 = (3M + 2N)(M + 3N)
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30×30=900
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3 years ago
Read 2 more answers
(15P) PLEASE HELP ME ASAP NEED HELP!
olya-2409 [2.1K]

Answer:

x=7

y=2

Step-by-step explanation:

10 + 2x = -2y ➡y = -5-x

replace y with -5-x in the first equation

-5-x-x = 9➡ -2x-5 = 9 ➡-2x = 9+5 ➡ x = -7

now use this information to find value of y

y - (-7)=9 ➡y = 2

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3 years ago
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kicyunya [14]
Part A: David wrote 0.003 + 0.0001 instead of <span>0.03 + 0.001 

Part B: T</span>he 1 should be in the thousandths place

Hope this helps, make sure to count each place from right after the decimal which is the tenths place, then hundredths, etc.
5 0
3 years ago
F Tanisha has ​$ 1,000 to invest at 5 % per annum compounded ​, how long will it be before she has ​$1,400 ​? If the compounding
vladimir2022 [97]

With annual compounding, the number of years for 1000 to become 1400 is 6.7 years

With continous compounding, the number of years for 1000 to become 1400 is 1.35 years

<h3>How long would it take $1000 to become $1,400?</h3>

With annual compounding, the formula that would be used is:

(In FV / PV) / r

Where:

  • FV = future value
  • PV = present value
  • r = interest rate

(In 1400 / 1000) / 0.05 = 6.7 years

With continous compounding, the formula that would be used is:

(In 1400 / 1000) / (In e^r)

Where r = interest rate

((In 1400 / 1000) / (In e^0.05) = 1.35 years

To learn more about how to determine the number of years, please check: : brainly.com/question/21841217

#SPJ1

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2 years ago
40 points PLZ HELP!
tiny-mole [99]

Answer:

178

Step-by-step explanation:

4 0
3 years ago
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