Answer:
this example of a box whisker plot
Step-by-step explanation:
try to input your numbers
"Regular quadrilateral" means it has four sides, and the
sides AND the inside angles are all equal.
-- The one at the upper left is a rhombus. All 4 of its sides
are the same length, and the first time I saw it, I picked it.
But then I remembered that in order to be 'regular', the
inside angles also have to be equal, and in a rhombus,
they're not.
-- The one in the lower right is a square. It has four sides,
they're all equal, and the inside angles are all the same too.
So the square is the only one that does the job for you.
3/x-1=2/x+4
Step 1:
Cross Multiply to get
3(x+4)=2(x-1)
Step 2:
Use distribute property
3x+12=2x-2
x=-14. Hope it help!
Answer:
x =9
Step-by-step explanation:
7x+3 = 6x + 12
x + 3 =12
x = 9
So both angles equal 66*
We will have the following:
First, we calculate AE as follows:
![AE=\sqrt[]{AM^2-EM^2}](https://tex.z-dn.net/?f=AE%3D%5Csqrt%5B%5D%7BAM%5E2-EM%5E2%7D)
Now, we replace values and solve it:
![AE=\sqrt[]{16^2-11^2}\Rightarrow AE=3\sqrt[]{15}](https://tex.z-dn.net/?f=AE%3D%5Csqrt%5B%5D%7B16%5E2-11%5E2%7D%5CRightarrow%20AE%3D3%5Csqrt%5B%5D%7B15%7D)
From theorem AE = EC therefore EC = esqrt(15); so, the following is true:
![AC=AE+EC\Rightarrow AC=2AE\Rightarrow AC=2(3\sqrt[]{15})\Rightarrow AC=6\sqrt[]{15}](https://tex.z-dn.net/?f=AC%3DAE%2BEC%5CRightarrow%20AC%3D2AE%5CRightarrow%20AC%3D2%283%5Csqrt%5B%5D%7B15%7D%29%5CRightarrow%20AC%3D6%5Csqrt%5B%5D%7B15%7D)
Knowing this, we then determine FA as follows:
![FA=\sqrt[]{AC^2-CF^2}](https://tex.z-dn.net/?f=FA%3D%5Csqrt%5B%5D%7BAC%5E2-CF%5E2%7D)
We then determine BE, DM & CM as follows: