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expeople1 [14]
3 years ago
12

A 1.5 pie B 3pie C 7.5pie D. 15 pie

Mathematics
1 answer:
frozen [14]3 years ago
3 0
Agreed I believe it’s c as well
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Which of the following point-slope form equations could be produced with the points (4, 5) and (-3, -5)?
NikAS [45]

Answer:

<em>Equation; y = 1 3 / 7x - 5 / 7</em>

Step-by-step explanation:

First consider the slope of this equation we must derive;

Slope Formula = Rise / Run,

y2 - y1 / x2 - x1 ⇒

5 - ( - 5 ) / 4 - ( - 3 ) ⇒

10 / 7 ⇒ Slope : 1 3 / 7

So far we can formulate an equation as such;

y = 1 3 / 7 * x + b, <em>where b ⇒ y - intercept</em>

Given one of the points, substitute into this equation solving for b;

5 = 1 3 / 7 * ( 4 ) + b,

5 = 40 / 7 + b,

b = - 5 / 7

From this we can derive one point - slope from equation to be :

<em>Equation; y = 1 3 / 7x - 5 / 7</em>

3 0
2 years ago
CAN SOMEONE HELP ME WITH THIS?!?!
Nat2105 [25]
.......................:)
7 0
3 years ago
Read 2 more answers
Find all of the points on the x-axis which are 6 units from the point (−1, 1).
anyanavicka [17]
All the points that are 6 units from (-1, 1) are those on the circle
  (x+1)^2 +(y-1)^2 = 36

For y=0, the two points of interest satisfy
  (x+1)^2 +1 = 36
  (x+1)^2 = 35 . . . . . . subtract 1
  x+1 = ±√35
  x = -1±√35

The points you seek are (-1-√35, 0) and (-1+√35, 0), about (-6.916, 0) and (4.916, 0).

5 0
3 years ago
. One car traveled 210 miles and drove 20 mph hour faster than a second car drove 150 miles. If the cars were traveling for the
inn [45]

Answer:

The first car was traveling 70 mph, while the second was driving 50 mph.

Step-by-step explanation:

Set the cars as a proportion:

\frac{210}{x + 2}  =  \frac{150}{x}

X represents the speed of the second car. By cross multiplying, you get the following equation:

210x = 150(x + 20)

You solve by distributing 150 to get 210x = 150x + 3000.

Solving for x gets you 50.

That means the first car was going at 50 mph. Adding 20, you get 70 as the speed for the second car.

4 0
2 years ago
Question 26 pleaseee
LuckyWell [14K]

Answer:

The inequality is 55+10x\leq 105

The greatest length of time Jeremy can rent the jet ski is 5 and Jeremy can rent maximum of 135 minutes.

Step-by-step explanation:

Given: Cost of first hour rent of jet ski is $55

          Cost of each additional 15 minutes of jet ski is $10

          Jeremy can spend no more than $105

Assuming the number of additional 15-minutes increment be "x"

Jeremy´s total spending would be first hour rental fees and additional charges for each 15-minutes of jet ski.

Lets put up an expression for total spending of Jeremy.

\$55+ \$ 10\times x

We also know that Jeremy can not spend more than $105

∴ Putting up the total spending of Jeremy in an inequality.

\$ 55+\$10x\leq \$ 105

Now solving the inequality to find the greatest number of time Jeremy can rent the jet ski,

⇒ \$ 55+\$10x\leq \$105

Subtracting both side by 55

⇒ \$ 10x\leq \$50

Dividing both side by 10

⇒x\leq \frac{50}{10}

∴ x\leq 5

Therefore, Jeremy can rent for 60\ minutes + 5\times 15\\= 60\ minutes + 75= 135\ minutes

Jeremy can rent maximum of 135 minutes.

5 0
3 years ago
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