A 1.5 pie B 3pie C 7.5pie D. 15 pie

Suppose you have a bag containing 2 black marbles and 3 red marbles. You reach into the bag, select a marble, see what color it

TiliK225 [7]

Answer:

$\dfrac{9}{25}$

Step-by-step explanation:

Given that the bag contains black and red marbles.

Number of black marbles in the bag = 2

Number of red marbles in the bag = 3

Total number of marbles in the bag = Number of black marbles + Number of red marbles = 2 + 3 = 5

Let us have a look at the formula for probability of an event E, which can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(\text{First red marble}) = \dfrac{\text{Number of red marbles}}{\text{Total number of marbles}} = \dfrac{3}{5 }$

Now, the marble chosen at first is replaced.

Therefore, the count remains the same.

$P(\text{Second red marble}) = \dfrac{\text{Number of red marbles}}{\text{Total number of marbles}} = \dfrac{3}{5}$

Now, the required probability can be found as:

$P(\text{First red marble})\times P(\text{Second red marble}) = \dfrac{3}{5}\times \dfrac{3}{5} = \bold{\dfrac{9}{25} }$

3 0

3 years ago

Hello please help i’ll give brainliest

Law Incorporation [45]

Answer:

the answer is d

Step-by-step explanation:

their competing for food so it's either d or c and lions and hyenas are different species so d

3 0

3 years ago

An object is launched from ground level with an initial velocity of 120 meters per second. For how long is the object at or abov

babunello [35]

Answer:

D) 14 seconds

Step-by-step explanation:

First we will plug 500 in for y:

500 = -4.9t² + 120t

We want to set this equal to 0 in order to solve it; to do this, subtract 500 from each side:

500-500 = -4.9t² + 120t - 500

0 = -4.9t²+120t-500

Our values for a, b and c are:

a = -4.9; b = 120; c = -500

We will use the quadratic formula to solve this. This will give us the two times that the object is at exactly 500 meters. The difference between these two times will tell us when the object is at or above 500 meters.

The quadratic formula is:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Using our values for a, b and c,

$x=\frac{-120\pm \sqrt{120^2-4(-4.9)(-500)}}{2(-4.9)}\\\\=\frac{-120\pm \sqrt{14400-9800}}{-9.8}\\\\=\frac{-120\pm \sqrt{4600}}{-9.8}\\\\=\frac{-120\pm 67.8233}{-9.8}\\\\=\frac{-120+67.8233}{-9.8}\text{ or }\frac{-120-67.8233}{-9.8}\\\\=\frac{-57.1767}{-9.8}\text{ or }\frac{-187.8233}{-9.8}\\\\=5.3242\text{ or }19.1656$

The two times the object is at exactly 500 meters above the ground are at 5 seconds and 19 seconds. This means the amount of time it is at or above 500 meters is

19-5 = 14 seconds.

6 0

3 years ago

Find the equation of a circle whose endpoints of the diameter are (15, - 3) and (7,3). The equation of the circle is (Simplify y

Nana76 [90]

Answer:

(x - 11)² + y² = 25

Step-by-step explanation:

First find the center

O = ( (15 +7 / 2), (-3 + 3)/2 )

O = (11, 0)

Then find the radius squared

use the distance formula from the center to either end point of the diameter

r² = (15 - 11)² + (-3 - 0)²

r² = 16 + 9

r² = 25

Formula for circle

(x - h)² + (y - k)² = r²

(h, k) is the center = (11, 0)

The equation is

(x - 11)² + y² = 25

8 0

3 years ago

Please help! The best answer will get brainly!

Vika [28.1K]

Answer:

9 outfits
6
6

Step-by-step explanation:

4 0

3 years ago

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