Answer: No, it can never be greater. At most it can be equal though.
The approximate area of the decagon with a side of 8cm comes to be 492.40 cm².
The side of the regular decagon = 8cm
<h3>What is a regular decagon?</h3>
A regular decagon is a polygon with 10 sides that are equal to each other.
The area of a regular decagon with side a is:

So, the area A of the regular decagon with a side of 8cm:


A=492.40 cm²
Therefore, the approximate area of the decagon is 492.40 cm².
To get more about the decagon visit:
brainly.com/question/19899848
19, 21, 23 are the consecutive odd numbers.
I did this by thinking that 63 divided by 3 is 20. Then I went to 21, and added it to 23, I got 44, so then I added 19 and got 63. (Adding 25 didn't help so I tried 19)