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Amanda [17]
3 years ago
9

A sequence of numbers a1, a2, a3, . . . is defined as follows: a1 = 3, a2 = 5, and every term in the sequence after a2 is the pr

oduct of all terms in the sequence preceding it, e.g., a3 = (a1)(a2) and a4 = (a1)(a2)(a3). If an = t and n > 2, what is the value of an+2 in terms of t ?
(A) 4t (B) t^2 (C) t^3 (D) t^4 (E) t^8
Mathematics
1 answer:
Dmitry [639]3 years ago
6 0

Answer:

  (D)  t^4

Step-by-step explanation:

You have defined ...

  a3 = a2·a1

  a4 = a3·(a2·a1) = a3²

  a5 = a4·(a3·a2·a1) = a4² = (a3²)² = a3⁴

Then if a3 = t, a5 = t⁴

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Need help with Number 11.Show your work plz.Please answer Quick.
Zanzabum
Jennifer earns $5.50 per hour

Edward earns ($5.50*1.8) $9.90 per hour

Edward earns more per hour

To find out how many hours they'd have to work to make 50$, we would just divide $50 by their hourly wage.

Jennifer=50/5.50=9.09 hours    since you cant have 0.09 hours round up
Jennifer=10 hours to make at least $50 dollars

Edward=50/9.90=5.05 hours    since you cant have 0.05 hours round up
Edward=6 hours to make at least $50 dollars


**Edit. Since Edward earns 1.8 times what Jennifer earns, that means he earns 180% of what she earns or 80% more. So we can tell that he earns more just by the 1.8.

1.8=180%
7 0
3 years ago
Which of the following is a correct interpretation of the expression -4 + 13−4+13minus, 4, plus, 13?
7nadin3 [17]

Answer:

Step-by-step explanation:

-4 + 13 - 4 + 13 - 4 + 13

9 - 4 + 13 - 4 + 13

5 + 13 - 4 + 13

18 - 4 + 13

14 + 13

27

6 0
3 years ago
The numbers of bags of crisps sold per day in a general shop was recorded over 13 days.
Alona [7]

I just figured it out so I’ll answer it on this account lol.

Q1 = 32, Q2 = 45, Q3 = 52

Interquartile range = 52 - 32 = 20

Range = 68 - 21 = 47

6 0
3 years ago
How to solve 5 + 5 x 5 -5 ÷ 5
blagie [28]

Answer:

= 5+5x5-25

=5+25 -25

=30-25

=5

7 0
3 years ago
Diana works in a building that is 130 feet tall. She is outside, looking up at the building at an angle of 37° from her feet to
AveGali [126]
Let x be her initial distance from the building, then tan 37 = 130/x
x = 130/tan 37 = 130/0.7536 = 172.5 feet

Let y be her distance from the building after moving forward, then
tan 40 = 130/y
y = 130/tan 40 = 130/0.8391 = 154.9

After moving forward, she is 172.5 - 154.9 = 17.6 ft closer.
4 0
3 years ago
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