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Sophie [7]
3 years ago
13

Ms Quon discovered that 40 students like soccer, 20 liked baseball, 10 liked football, and 5 liked swimming.

Mathematics
1 answer:
LiRa [457]3 years ago
7 0
1.\ 20:10=2\\2\ many\ times\ of\ students\ liked\ baseball\ as\ football\\\\2.\ 40:10=4\\4\ many\ times\ of\ students\ liked\ soccer\ as\ football\\\\3.\ There\ is\ no\ information\ about\ basketball\ students
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A soldier started patrolling around his camp at 22 30 . His patrol lasted 3 hours and 20 minutes .What time did his patrol end
baherus [9]

Answer:01 50 Hrs

Step-by-step explanation:

If the soldier started patrol at 2230 hrs and his petrol lasted for 3 hours and 20 minutes, that means he was on patrol for that time.

The time he finished was therefore:

= 2230 + 320

= 2550

At 24 you begin at 0:00am so:

= 2550 - 2400

= 150

Patrol ended at 0150 hrs

4 0
3 years ago
Identify the point from the equation y+2=5(x-5)
Oxana [17]

Answer:

use desmos :)) it helps

Step-by-step explanation:

8 0
3 years ago
A data set includes 103 body temperatures of healthy adult humans having a mean of 98.3degreesF and a standard deviation of 0.73
faust18 [17]

Answer:

CI = (98.11 , 98.49)

The value of 98.6°F suggests that this is significantly higher

Step-by-step explanation:

Data provided in the question:

sample size, n = 103

Mean temperature, μ = 98.3

°

Standard deviation, σ = 0.73

Degrees of freedom, df = n - 1 = 102

Now,

For Confidence level of 99%, and df = 102, the t-value = 2.62      [from the standard t table]

Therefore,

CI = (Mean - \frac{t\times\sigma}{\sqrt{n}},Mean + \frac{t\times\sigma}{\sqrt{n}})

Thus,

Lower limit of CI =  (Mean - \frac{t\times\sigma}{\sqrt{n}})

or

Lower limit of CI =  (98.3 - \frac{2.62\times0.73}{\sqrt{103}})

or

Lower limit of CI = 98.11

and,

Upper limit of CI =  (Mean + \frac{t\times\sigma}{\sqrt{n}})

or

Upper limit of CI =  (98.3 + \frac{2.62\times0.73}{\sqrt{103}})

or

Upper limit of CI = 98.49

Hence,

CI = (98.11 , 98.49)

The value of 98.6°F suggests that this is significantly higher and  the mean temperature could very possibly be 98.6°F

7 0
3 years ago
The product of two numbers is a ______ of both numbers
qwelly [4]
<h2>The product of two numbers is <em>a,</em>  \sqrt{a} of both numbers.</h2>

Step-by-step explanation:

Given,

The product of two numbers = a

To find, the both numbers = ?

Let the two numbers = x

∴ x × x = a

⇒ x^{2} =  a

⇒ x^{2} =\sqrt{a}^2

Comparing the powers, we get

⇒ x = \sqrt{a}

∴ First number = \sqrt{a} and Second number = \sqrt{a}

Thus, the product of two numbers is <em>a,</em>  \sqrt{a} of both numbers.

5 0
3 years ago
Solve the following problems. Given: AB ≅ BC and AE = 10 in, m∠FEC = 90° m∠ABC = 130°30' Find: m∠EBC, AC http://homework.russian
horrorfan [7]

Because BA ≅ BC, we know the triangle is isosceles. Because ∠FEC=90°, we know BE is a median and angle bisector of ∠ABC.

Hence ...

... AC = 2×AE = 20 in

... ∠EBC = (1/2)×∠ABC = 65°15'

7 0
3 years ago
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