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mr_godi [17]
3 years ago
6

Find the real numbers x and y that make the equation true. -3 + yi = x + 6i

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
6 0
What are the options?

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ikadub [295]
What are you asking to solve?
6 0
2 years ago
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I have a question that says " jada has read 3/5 of a book. She has read 75 pages so far. How many pages are in the whole book?"
jok3333 [9.3K]

Answer and Step-by-step explanation:

To solve, we would multiply by the reciprocal of the portion Jada has read, and multiply that number to 75.

The reciprocal means the the value, but flipped, so \frac{3}{5} will become \frac{5}{3}.

Now we do 75 times \frac{5}{3}/

\frac{75 * 5}{3} \\\\\\\\\frac{375}{3} \\\\\\\\125

So, there are 125 total pages in the book.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

3 0
3 years ago
One angle of a parallelogram measures 110°. What are the measures of the other three angles in the parallelogram?
Art [367]

Answer:

70, 110, 70

Step-by-step explanation:

The measures of the adjacent angles of a parallelogram always add up to be 180 degrees (they are supplementary).

4 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST!!(plz show work too)
trapecia [35]

\huge \bf༆ Answer ༄

Let the capacity of bus be x students

And van be y students, now ;

From the given statements we get two equations ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \:   \:  \:  \: \:  (1)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:13x + 5y = 670 \:  \:  \:  \:  \: (2)

multiply the equation (2) with 2 [ it won't change the values ]

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \: \:  \:  \:   \:  \:  \:  \:  \: (1)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:26x + 10y = 1340 \:  \:  \:  \:  \: (3)

Now, deduct equation (1) from equation (3)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:26x + 10y - 2x - 10y = 1340 - 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:24x = 1080

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 1080 \div 24

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 45

Therefore each bus can carry (x) = 45 students

Now, plug the value of x in equation (1) to find y ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:(2 \times 45) + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:90 + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:10y = 260 - 90

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:10y = 170

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 170 \div 10

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 17

Hence, each van can carry (y) = 17 students in total.

5 0
2 years ago
Andresssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss
Leviafan [203]

Answer:

Anderess?

Step-by-step explanation:

3 0
2 years ago
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