Question

Graph y < 1/3x + 1/2

Answer 1

Answer:

Observe the attached image

Step-by-step explanation:

The limit of inequality is marked by the equation of the line

$y = \frac{1}{3}x +\frac{1}{2}$

Therefore the first step to graph the inequality is to graph the line

$y = \frac{1}{3}x +\frac{1}{2}$

First we find its cut point with the x axis. (y = 0)

$0 = \frac{1}{3}x +\frac{1}{2}$

$-\frac{1}{2}= \frac{1}{3}x$

$x =\frac{-\frac{1}{2}}{\frac{1}{3}}\\\\x = -\frac{3}{2}$

Second we find its cut point with the y axis. (x = 0)

$y= \frac{1}{3}(0) +\frac{1}{2}$

$y =\frac{1}{2}$

Now that we know the cut points, we can graph the line.

Then, the inequality

$y$

it tells us that the region is made up of all the values of y that are smaller or that are below the equation of the line $y = \frac{1}{3}x +\frac{1}{2}$.

In this way we shadow the region that is below the line and this will be the graph of the inequality. Observe the attached image