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ICE Princess25 [194]
2 years ago
5

if post are spaced 10 feet apart for a straight-line fence of 100 feet,then you would need how many post to hang the fence?

Mathematics
1 answer:
Nadusha1986 [10]2 years ago
4 0

Answer:

There are 11. Remember, there's a post at the very beginning of the fence, and one at the very end. So it's (fence length / 10) + 1 = (100 / 10) + 1 = 10 + 1 = 11.

They're positioned along the fence at the following distances from the start:

0 ft, 10 ft, 20 ft, ..., 100 ft.

That's probably why the question specified "straight-line fence". If it was in a decagon (10-sided polygon shape, so sort of round-ish), the first post could also serve as the last post, and there could be only 10 posts. But in a straight line, there have to be 11.

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an octagon has sides that all have a length of y. Write a simplified algebraic expression for the perimeter of the octagon in te
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Step-by-step explanation:

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5 0
3 years ago
You plant a rectangular rose garden along the side of your garage. You enclose 3 sides of the garden with 40 feet of fencing. Th
solmaris [256]

Let's assume

length of rectangle =L

width of rectangle =W

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so, we get

L+2W=40

now, we can solve for L

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we know that

area of rectangle is

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100=L*W

now, we can plug

100=(40-2W)*W

now, we can solve for W

-2W^2+40W-100=0

we can use quadratic formula

W=\frac{-40+\sqrt{40^2-4\left(-2\right)\left(-100\right)}}{2\left(-2\right)}

W=\frac{-40-\sqrt{40^2-4\left(-2\right)\left(-100\right)}}{2\left(-2\right)}

we can take anyone value ..because both are giving positive value

first dimensions:

W=2.929

now, we can find L

L=40-2*2.929

L=34.142

so, length is 34.142feet

width is 2.929 feet

Second dimensions:

W=17.071

now, we can find L

L=40-2*17.071

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so, length is 5.858feet

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6 0
3 years ago
Пожалуйста помогите с решением
zubka84 [21]

Answer:

( x, y) =

65 \ \frac{15}{11}

this is your answer

3 0
2 years ago
X + 54 = 37 so X = ?
Troyanec [42]

Answer:

x=-17

Step-by-step explanation:

x+54=37

-54. -54

x=-17

4 0
2 years ago
Read 2 more answers
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