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3241004551 [841]

4 years ago

6

Pleas help. I only have 3 minutes left and i really dont get it. An estate agent has three houses for sale. The prices of the ho

uses were
in the ratio 6:4:3 and the cheapest house was priced at $240 000. What
were the prices of the other two houses? (SHOW WORKING)

1 answer:

ra1l [238]4 years ago

7 0

Answer:

d a m n been 5 minutes

Step-by-step explanation:

wanna talk

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Answer:

A 1/3

Step-by-step explanation:

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3 years ago

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A bag contains 4 Red, 5 Black and 2

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Answer:

$P( 2 \ green ) = \frac{4}{121}$

Step-by-step explanation:

$Probability \ of \ green \ i n \ the \ first \ try = \frac{2C_1}{11C_1} = \frac{2}{11}\\\\Probability \ of \green \ i n \ the \ Second \ try = \frac{2C_1}{11C_1} = \frac{2}{11}\\\\Probability \ of \ 2 \ green = \frac{2}{11} \times \frac{2}{11 } = \frac{4}{121}$

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3 years ago

-4 (2y+4) + 6y = -10

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3 years ago

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Express 60% as a decimal<br> a. 0.4 b. 0.06 c. 0.65 d. 0.6 please explain

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<h2>Answer: D. 0.6</h2>

Step-by-step explanation:

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3 years ago

The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

$A(-2, 2),B(6, 2),C(0, 8)$

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

$P=AB+BC+AC$

and

the area of the triangle is equal to

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB\\heigth=DC$

we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

<u>Find the distance AB</u>

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$dAB=8\ units$

Step $2$

<u>Find the distance BC</u>

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

$dBC=6\sqrt{2}\ units$

Step $3$

<u>Find the distance AC</u>

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

$dAC=2\sqrt{10}\ units$

Step $4$

<u>Find the distance DC</u>

$D(0, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

$dDC=6\ units$

Step $5$

<u>Find the perimeter of the triangle</u>

$P=AB+BC+AC$

substitute the values

$P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units$

$P=22.81\ units$

therefore

The perimeter of the triangle is equal to $22.81\ units$

Step $6$

<u>Find the area of the triangle</u>

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB=8\ units\\heigth=DC=6\ units$

substitute the values

$A=\frac{1}{2}*8*6$

$A=24\ units^{2}$

therefore

the area of the triangle is $24\ units^{2}$

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3 years ago

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