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3 years ago

How do I add: 1/3+1/4?

Mathematics

2 answers:

vlada-n [284]3 years ago

6 0

You convert the denominator into a common number. That is 12. You then add 4/12 + 3/12 = 7/12

inn [45]3 years ago

3 0

Get a common factor which would be 12.... the equation is now 4/12 + 3/12 which is 7/12

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Mr. Fishie bought a tank for $15 and 10 fish which cost $f each. If he gave the cashier two 20-dollar bills, what was his change

Gnesinka [82]

Answer:

$25 - $10f

Step-by-step explanation:

Fishie's name is fishy.

We know Mr. Fishie spent $15 on a tank. His 10 fish cost 10*$f. His total is:

Total =15 + 10*f

His change after 2 $20 would be:

$40 - ($15 - $10f), or

$25 - $10f

3 0

2 years ago

Solve the following equation: x÷3-5=-7

Elodia [21]

Answer:

- 6

Step-by-step explanation:

Step 1:

x ÷ 3 - 5 = - 7 Equation

Step 2:

x ÷ 3 = - 2 Add 5 on both sides

Answer:

x = - 6 Multiply 3 on both sides

Hope This Helps :)

3 0

3 years ago

How do you get 85 tens in 23 ones in standard form ?

Andrew [12]

The answer is 873 hope this will help you.

7 0

3 years ago

Read 2 more answers

In 2000, U.S. Airways burned about 115 litres of fuel per passenger. In 2014 that dropped

ankoles [38]

Answer:

22% reduction

Step-by-step explanation:

Find the percent decrease by dividing the difference in amounts by the original amount.

Find the difference:

115 - 90 = 25

Divide this by the original amount:

25/115

= 0.217

So, the percent decrease is 21.7%. Round this to the nearest whole percentage:

= 22

The percent reduction in fuel used was approx. 22%

6 0

3 years ago

A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet

Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

$L_{1} = 2W_{1}$

Also, the area of the walkway of 2 feet wide is 448:

$W_{2} = 2 ft$

$A_{T} = W_{2}*L_{2} = 448 ft^{2}$

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

$A_{T} = A_{1} + A_{w}$ (1)

The area of the pool is given by:

$A_{1} = L_{1}*W_{1}$

$A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}$ (2)

And the area of the walkway is:

$A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}$ (3)

Where the length of the bigger rectangle is related to the lower rectangle as follows:

$L_{2} = 4 + L_{1} = 4 + 2W_{1}$ (4)

By entering equations (4), (3), and (2) into equation (1) we have:

$A_{T} = A_{1} + A_{w}$

$A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}$

$448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}$

$224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}$

$224 = W_{1}^{2} + 8 + 6W_{1}$

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

$L_{1} = 2W_{1} = 2*12 ft = 24 ft$

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!

8 0

3 years ago