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mars1129 [50]
3 years ago
13

MZB = xo, what is the measure of a supplement of LB?

Mathematics
1 answer:
Jet001 [13]3 years ago
5 0

9514 1404 393

Answer:

  supplement of ∠B = 180° -x°

Step-by-step explanation:

The supplement of an angle is the difference between 180° and that angle.

  supplement of ∠B = 180° - m∠B

  supplement of ∠B = 180° -x°

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The table below represents the distance of a car from its destination as a function of time.
KIM [24]
We are given the table that projects the distance of the car per hour. x is associated to time while y is associated to distance. The equation of the line after plotting in MS Excel is y = 900 - 50x. Hence the y-intercept is equal to 900 while the slope is equal to -50. The domain of the function that is x is all positive numbers. 
7 0
3 years ago
Need some help with this question in the image<br><br>Cheers​
iren [92.7K]

Step-by-step explanation:

a) 24.7×52.3=1291.81

On rounding off to 3 significant digits we get

1290

b)

\sqrt{ {42}^{2} -  {28}^{2}  }

\sqrt{1764 -784 }  =  \sqrt{980}

=31.304951

On rounding off to 5 significant figures we get

=31.305

c)

\sqrt[3]{78}  = 4.27265

On rounding off to 2 significant figures we get

=4.3

Hence required answers

a)1290

b)31.305

c)4.3

I hope it helped you

5 0
2 years ago
Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour
UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

C(t) = C(0)e^{rt}

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So C(0) = 110

Husband

Half life of 4 hours. So

C(4) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{4r}

e^{4r} = 0.5

Applying ln to both sides

\ln{e^{4r}} = \ln{0.5}

4r = \ln{0.5}

r = \frac{\ln{0.5}}{4}

r = -0.1733

So for the husband

C(t) = 110e^{-0.1733t}

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.1733t}

C(11) = 110e^{-0.1733*11} = 16.35

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

C(10) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{10}

e^{10r} = 0.5

Applying ln to both sides

\ln{e^{10r}} = \ln{0.5}

10r = \ln{0.5}

r = \frac{\ln{0.5}}{10}

r = -0.0693

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.0693t}

C(11) = 110e^{-0.0693*11} = 51.33

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0
3 years ago
A game involves rolling a fair six-sided die. If the number facing upward on the die is a whole number multiple of three, the pl
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I would say about $10 about 1/6th the time
4 0
3 years ago
Read 2 more answers
Michelle and matthew bake carrot cake at their bakery. For every 9 cups of shredded carrots they use, they use 6 cups of sugar.
Anvisha [2.4K]

Answer: 21 cups of shredded carrots.

Step-by-step explanation:

For every 9 cups of shredded carrots they use, they use 6 cups of sugar.

To use one cup of sugar therefore, the number of cups of shredded carrot is:

= 9/6

= 1.5 cups of shredded carrot

For every 1.5 cups of shredded carrot, a cup of sugar is used.

If they were to use 14 cups of sugar, they would therefore use:

= 14 * 1.5 cups of carrot

= 21 cups of shredded carrot

4 0
3 years ago
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