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ser-zykov [4K]
3 years ago
9

Find The Difference [Will Give Brainliest If Correct]

Mathematics
1 answer:
RUDIKE [14]3 years ago
7 0

Answer:

30, 10, -10

Step-by-step explanation:

Subtract each number below from the number above.

60 - 30 = 30

50 - 40 = 10

40 - 50 = -10

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Word bank please help
anastassius [24]
X rays=E
Microwaves=A
Gamma rays=C
Radio waves=F
Infrared waves=D
Ultraviolet waves=B
8 0
2 years ago
The rabbit population in a certain area is 200​% of last​ year's population. There are 900 rabbits this year. How many were ther
Nezavi [6.7K]

There would be 450 rabbits last year.

Since 900 is double 450, 200% of 450 is 900. (450 would be 100%, so you would double it).

3 0
3 years ago
Find the volume of the figure below.
skad [1K]
Volume\ =  \frac{4}{3} \pi r^3 =  \frac{4}{3} \times \frac{22}{7} \times 15^3 =  \boxed{14137.17\ ft^3}
8 0
3 years ago
Find the equation of a line that contains the points (3,7) and (-6, 4). Write the equation in slope-intercept form, using
NikAS [45]

Answer:

y=\frac{1}{3} x+6

Step-by-step explanation:

(3,7)(-6,4)

Step 1. Find the slope (by using the slope-formula)

m = slope

m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{4-7}{-6-3}

m=\frac{-3}{-9}

m=\frac{3}{9}

m=\frac{1}{3}

Step 2. Write the equation (using the slope and the points)

Here's how to do it:

Slope-intercept Formula y=mx+b whrere m = slope and b = y-intercept

Plug in the slope into the Slope-intercept Formula

y=\frac{1}{3} x+b

Find the y-intercept (b) by using a point and substituting their x and y values

y=\frac{1}{3} x+b

Point: (3, 7)

7=\frac{1}{3} (3)+b

7=1+b

b=7-1

b=6

Step 3. Write the equation in Slope-intercept form

y=mx+b

y=\frac{1}{3} x+6

3 0
2 years ago
Is (11,9), (11,5), (9,3) a function
Marina86 [1]

Answer:

\huge{ \boxed{ \sf{No}}}

✑ Question :

  • Is ( 11 , 9 ) , ( 11 , 5 ) , ( 9 , 3 ) a function ?

No , it's not a function.

✎ Reason :

This is not a function because one element 11 of set A is associated to elements 9 and 5 of set B.

♨ Explore about function :

↪ Function is a special type of relation. It is the refinement of relation. In a relation from A to B , every element of set A should have only one ( distinct ) image in B to be a function. In other words , if no two different ordered pairs have the same first component , then it is a function.

Hope I helped!

Have a wonderful day ! ツ

~\sf{TheAnimeGirl} ♡

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

7 0
2 years ago
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