Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.
-2x+3y=-6 Add 2x in both sides
3y=2x-6 Divide by 3 in both sides to isolate y
y=2/3x-6/3
The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.
y=mx+b Substitute the given point and the previous slope found
-2=(-3/2)(6)+b Combine like terms
-2=-9+b Add 9 in both sides to isolate b
7=b
The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.
Answer:
C is the answer
Step-by-step explanation:
just took the quiz
brainlest please
I got C for 6 & 7. I haven't done this in a while so I don't know 8 & 9. I hope I helped!
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Answer:
a = 1
Step-by-step explanation:
The slope of the inverse of a linear function is the inverse of the slope of the original function.
The slope of g(x) is the coefficient of x: 1.
The inverse of 1 is 1/1 = 1.
The slope of the function g^-1(x) is 1, so a=1.
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<em>Additional comment</em>
g^-1(x) = x +65 . . . . . a=1; b=65
Answer: C) 10x + 25
<u>Step-by-step explanation:</u>
f(x) = <u> 2x + 5 </u>, g(x) = <u> 5 </u>
(fg)(x) = (2x + 5) * 5
= 10x + 25
