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Nikitich [7]
3 years ago
11

Prove that the diagonals of a rectangle bisect each other. the midpoint of is _____

Mathematics
1 answer:
Deffense [45]3 years ago
8 0
In this attached picture, we can prove that triangles AOB and COD are congruent. ∠CDO and ∠ABO are equal because they are alternate angles. Similarly, ∠OAB and ∠OCD are equal because they are alternate angles, as well. We have a rectangle and in the rectangle, opposite sides are equal; AB = CD. Then, because of Angle-SIde-Angle principle, we can say that triangles AOB and COD are equal. If triangles are congruent, then OD = OB and OC = AO. Applying congruency to the triangles ACD and BCD, we can see that these triangles are also congruent. It means that the diagonals are equal. Since, OD = OB and OC = AO, it proves that the point O simultaneously is the midpoint and intersection point for the diagonals. 

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The sides of a triangle are 3x+ 2, 6x, and 5x. Find the expression to represent the perimeter. To find the perimeter, we ADD the
frosja888 [35]

Answer:

14x + 2

Step-by-step explanation:

Perimeter = sum of the measures of each side

If a triangle has side lengths of 3x+ 2, 6x, and 5x then the perimeter of that triangle is equal to 3x + 2 + 6x + 5x

Notice that the expression 3x + 2 + 6x + 5x has similar terms so to get the simplist version of the perimeter we would simply combine like terms

3x + 6x + 5x = 14x

The perimeter would = 14x + 2

7 0
3 years ago
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Please help me I really need help
Fofino [41]

Answer:

A, C

Step-by-step explanation:

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

the ∠A is adjacent (adj) to  AB and opposite (Opp) of BC and AB is the hypotenuse (Hyp) of the triangle

which one of the above trig functions fits that?

sin(Ф) = BC / AC   is sin(Ф)= Opp / Hyp , so choice A) works

cos(Ф) = BC / AC  is not cos(Ф) = Opp / Hyp  so choice B) does not work

cos(Ф) = BA / AC  is cos(Ф) = Adj / Hyp  so choice C)  works

AC / BC is just a ratio   it's not the angle , so D) doesn't work

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Anna35 [415]

Answer:

What's the question?

Step-by-step explanation:

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3 years ago
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What is an example of an object that you would want to have a large volume? Why?
wel

Answer:

a pool since it has a large volume

Step-by-step explanation:

8 0
3 years ago
2) The results of a 2012 Pew Foundation survey of high school and middle school teachers is given in the pie chart. A student as
Serggg [28]

Answer:

The calculated value z =  9.4451 > 1.96 at 5% level of significance.

Null hypothesis is rejected at 5% level of significance

yes there is  difference in the distribution of types of cell phones for the teachers in 2018 at a 5% level of significance

Step-by-step explanation:

<u>Explanation</u>:-

<u>Step:- (1)</u>

The results of a 2012 Pew Foundation survey of high school and middle school teachers is given in the pie chart.

A student asked a random sample of teachers in 2018 and found 165 had smart-phones, 80 had a cell phone

The first sample proportion

                                  p_{1} = \frac{80}{165} = 0.4848

A student asked a random sample of teachers in 2018 and found 165 had smart-phones,5 had no cell phone

The second sample proportion

                                p_{2} = \frac{5}{165} = 0.03030

<u>Step :-(ii)</u>

<u>Null hypothesis :H₀</u>: Assume that there is no difference in the distribution of types of cell phones for the teachers in 2018

H₀ : p₁ = p₂

<u>Alternative hypothesis :H₁</u>

H₁ : p₁ ≠ p₂

<u>Level of significance : ∝=0.05</u>

The tabulated value z=1.96

<u>Step:-(iii)</u>

The test statistic

                       Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }  } +\frac{1}{n_{2} } )} }

   where p = \frac{n_{1}p_{1} +n_{2} p_{2}  }{n_{1} + n_{2} }

              q = 1-p

 In given data n₁ = n₂ = n

              p = \frac{165 (0.4848)+165 (0.03030  }{165 + 165}

   on calculation , we get      p =  0.2655

                                                 q =1-p = 1-0.2655

                                                  q = 0.7345

                 

                    Z = \frac{0.4848 -0.030}{\sqrt{0.2655X0.7345(\frac{1}{165 }  } +\frac{1}{165} )} }

                    Z =   9.4451

The calculated value z =  9.4451 > 1.96 at 5% level of significance.

<u>Conclusion:</u>-

Null hypothesis is rejected at 5% level of significance

yes there is  difference in the distribution of types of cell phones for the teachers in 2018 at a 5% level of significance

6 0
4 years ago
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