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Mathematics

1 answer:

s344n2d4d5 [400]3 years ago

7 0

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☺ Hello mate__ ❤

◾◾here is your answer...

i think right question is this

(3x − 7y)^2

ok now start solving:-

(3x − 7y)^2

=> (3x − 7y) (3x − 7y)

=> 3x(3x- 7y) -7y(3x-7y)

=>. 3x.3x - 3x.7y-7y. 3x + 7y.7y

=> 9x^2 -27xy +27xy + 49y^2

=> 9x^2 + 49y^2

so your correct ans. is 9x2 + 49y2

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I hope, this will help you.☺

Thank you______❤

✿┅═══❁✿ Be Brainly✿❁═══┅✿

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Consider the force field and circle defined below.

grin007 [14]

By Green's theorem,

$\displaystyle\int_{x^2+y^2=9}\vec F(x,y)\cdot\mathrm d\vec r=\iint_D\left(\frac{\partial(xy)}{\partial x}-\frac{\partial(x^2)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=\iint_Dy\,\mathrm dx\,\mathrm dy$

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Convert to polar coordinates, taking

$\begin{cases}x=r\cos\theta\\y=r\sin\theta\end{cases}\implies\mathrm dx\,\mathrm dy=r\,\mathrm dr\,\mathrm d\theta$

Then the work done by $\vec F$ on the particle is

$\displaystyle\iint_Dy\,\mathrm dx\,\mathrm dy=\int_0^{2\pi}\int_0^3(r\sin\theta)r\,\mathrm dr\,\mathrm d\theta=\left(\int_0^{2\pi}\sin\theta\,\mathrm d\theta\right)\left(\int_0^3r^2\,\mathrm dr\right)=\boxed0$