A spaceship approaches the earth with a speed 0.50c. A passenger in the spaceship measures his heartbeat as 70 beats per minute.
What is his heartbeat rate according to an observer that is at rest relative to the earth
1 answer:
Answer:
61 bpm
Explanation:
By applying the relativistic Doppler Effect;
where;
frequency (f) = the heartbeat rate according to an observer that is at rest relative to the earth
= initial frequency of the heart beat = 70 beats per minutes (70 bpm)
v = speed of the spacecraft = 0.50 c
c = speed of the light
Replacing our values in the above equation; we have:
<em>f</em> = 60.62 bpm
<em>f </em>≅ 61 bpm
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