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Natalija [7]
4 years ago
9

How many numbers between 1 and 100 (inclusive ) are divisible by 5 or 3?

Mathematics
2 answers:
jeka944 years ago
5 0

Answer:

33 and 19

Step-by-step explanation:

there are 33 numbers between one and one hundred divisible by 3 and 19 numbers divisible by 5

zvonat [6]4 years ago
5 0

Answer:

47

Step-by-step explanation:

There are 20 numbers divisible by 5 between 1 and 1001, and 33 numbers divisible by 3 between 1 and 100.

So, you might think there are 20 + 33 = 53 numbers divisible by one or the other, but this is overcounting something.

We're counting every number which is divisible by both 5 and 3 twice. So, for example, 15 is counted once as a number divisible by 5, and then again as a number divisible by 3.

So, we need to count how many numbers are divisible by both 5 and 3 and subtract this from what we had before.

Being divisible by both 5 and 3 is the same thing as being divisible by 15, so there are 6 numbers between 1 and 100 divisible by both.

Subtracting, there are 53 - 6 = 47 numbers divisible by 5 or 3.

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Timothy has $500. He spends $50 each week on
earnstyle [38]

Answer:

It takes 10 weeks to spend each $500

Step-by-step explanation:

If he spend $50 each week on groceries, we can say that he spend $100 on groceries every two weeks

To make it to 500 dollars we would have to use the equation 100x5.

This equals to 500

We could also do 100 plus 100 plus 100 plus 100 plus 100.

8 0
3 years ago
The graph below shows the distance, y, that a car traveled in x hours:
Vika [28.1K]
This is a linear relationship as the rate of change is constant, ie constant velocity.  And the slope represents the velocity, and slope is:

m=(y2-y1)/(x2-x1)

m=(50-25)/(2-1)=25/1

m=25

So the rate of change is 25 mph
5 0
3 years ago
Read 2 more answers
Limit b⇒0 (Sin b)/b³
Nitella [24]

Answer:

infinity

Step-by-step explanation:

Given the function

Limit b⇒0 (Sin b)/b³

First substitute the value of b into the function to have

Limit b⇒0 (Sin b)/b³

= sin 0/0³

= 0/0 (Ind)

Apply lhospital rule

Limit b⇒0 (d./db(Sin b))/(d/db(b³))

=>Limit b⇒0 (cos b)/3b²

Substitute the value of b

Cos 0/3(0)²

= 1/0

= infinity

Hence the answer is infinity

4 0
3 years ago
Type the standard form of three hundred thousand two hundred one
leonid [27]

━━━━━━━━━━━━━━━ ♡ ━━━━━━━━━━━━━━━  

Standard form is numbers only.

Examples of standard numbers are 4, 225, or 9,002

A thousands number has 4 digits.

A hundreds number has 3 digits.

A tens number has 2 digits.

A regular number has 1 digit (itself).

Three hundred means 300.

Three hundred thousand, would be 300 times 1,000 (one thousand), or adding 3 zeros.

Two hundred is 200.

One is 1.

300 times 1,000 is 300,000.

300,000 and 200 is 300,200.

If the ones digit has a 1, then the number is 300,201.

Three hundred thousand, two hundred one written in standard form is 300,201.

━━━━━━━━━━━━━━━ ♡ ━━━━━━━━━━━━━━━  

5 0
3 years ago
Read 2 more answers
Beth has 36 GB of memory on her phone. She has used 35 GB of memory so far. She wants to download a game that requires 3 GB of m
sineoko [7]

Answer:

2 GB Remaining

Step-by-step explanation:

35 - 4 + 3 = 34

7 0
3 years ago
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