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Natalija [7]
3 years ago
9

How many numbers between 1 and 100 (inclusive ) are divisible by 5 or 3?

Mathematics
2 answers:
jeka943 years ago
5 0

Answer:

33 and 19

Step-by-step explanation:

there are 33 numbers between one and one hundred divisible by 3 and 19 numbers divisible by 5

zvonat [6]3 years ago
5 0

Answer:

47

Step-by-step explanation:

There are 20 numbers divisible by 5 between 1 and 1001, and 33 numbers divisible by 3 between 1 and 100.

So, you might think there are 20 + 33 = 53 numbers divisible by one or the other, but this is overcounting something.

We're counting every number which is divisible by both 5 and 3 twice. So, for example, 15 is counted once as a number divisible by 5, and then again as a number divisible by 3.

So, we need to count how many numbers are divisible by both 5 and 3 and subtract this from what we had before.

Being divisible by both 5 and 3 is the same thing as being divisible by 15, so there are 6 numbers between 1 and 100 divisible by both.

Subtracting, there are 53 - 6 = 47 numbers divisible by 5 or 3.

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nikitadnepr [17]

ANSWER : 9 over 4

or 2 and 1/4

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

*3 over 2 x 3 over 2 is 3/2 x 3/2* << this is for me to remember

Okay so multiplying fractions means for us to multiply across. That means if we line the fractions, we multiply. Like this

 3     x     3

-----         -----                3 times 3 is = 9

 2     x     2                  2 times 2 is = 4

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8 0
3 years ago
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if 5 litres of water are drawn from a cylindrical container of internal diameter 56cm find the drop in the level of water in the
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Answer:

the drop in the level of water in the container is 2.03 cm

Step-by-step explanation:

The volume of a cylinder can be written as;

V = \pi r^2h=\frac{\pi d^2h}{4}  \\where;\\r = radius \\h = height \\d = diameter

the change in height when the volume changes can be derived by differentiating the equation.

dV =\frac{\pi d^2}{4} dh\\dh = dV\frac{4}{\pi d^2}

substituting the given values;

\left \{ {{dV=5 litres= 5000cm^3} \atop {d=56 cm}} \right.

dh = 5000\frac{4}{\pi * 56^2}\\dh = 2.03cm

the drop in the level of water in the container is 2.03 cm

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