Answer:
You could say something like, "My servey answers I got were a little bit different then the results in the artical. This may be because the pople I asked have different oppinions on this subject. Also. . . "Insert Something About The Margin Errors Here". . .That is how my results compare to the results in the passage and why they are different.
Step-by-step explanation:
I'm not sure if this is the format u want though.
1/12
There is 1 side of the die that has a ten on it and 12 sides in total. Therefore, there is a 1/12 chance of rolling a ten on this die.
The change is decay and the percentage rate of decrease will be 95%.
An exponential function is a function where a number is raised to the variable i.e. base is raised to the exponent times.
Here given the exponential function is y= 4300(0.042)ˣ
Now we have to identify if the change in exponential function represents growth or decay, and have to determine the percentage rate of increase or decrease.
Here in the exponential function, the base is less than 1 so the change is decay.
The equation represents exponential decay because the decay factor is lesser than 1.
The general form of the exponential equation is:
y(x)= a(1-r)ˣ such that r is the decay.
equating with the equation
y= 4300(0.042)ˣ
a= 4300
and 1-r=0.042
⇒r= 1-0.042
⇒r= 0.958
the perecentage of decay will be r*100= 0.958*100= 95%
Therefore the change is decay and the percentage rate of decrease will be 95%.
Learn more about exponential function
here: brainly.com/question/2046253
#SPJ10
Sequence 1,5,9,13,...
A(0) = 1 +4x0=1
A(1) =1 + 4x1 = 5
A(2) = 1+ 4x2= 9
A(3) = 1 +4x3=13
A(n)= 1+4n A(n-1) = 1+4(n-1) =1+4n-4= - 3+4n
A(n) - A(n-1) = (1+4n) - (-3=4n) = 4
A(n) = A(n-1) +4; 29 is the answer
The error bound for a trapezoid rule is given with this formula:

Where n is the number of points we used in the approximation, a and b are starting and ending point of an integral, and K is the number such that:

In order to find K we must find the second derivative of our function:

From this, we can see that our K is 120. This is the amplitude of this periodic function.
Now we can calculate the error bound:

Since you did not specify the interval of integration I cannot compute the final error bound. You can simply plug in the numbers to get the answer.