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3 years ago

X-6y-2z= 7 -2x+5y-2z= -1 -5x+6y+5z= -6

Mathematics

1 answer:

emmasim [6.3K]3 years ago

5 0

Answer:

do you need the value of x?

x=7+6y+2z

-2(7+6y+2z)+5y+2z=-1 -7y=13+2z

-14-12y-4z+5y+2z=-1

-14-7y-2z=-1

-7y-2z=-1+14

-7y-2z=13

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Four wholesalers are having specials on chicken this week.

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Answer:

Wholesaler A.

Step-by-step explanation:

First, put the pounds and dollars into fraction form. Then simplify those fractions. Finally, convert the fractions into decimals and compare the unit prices for each wholesaler. Whichever one is the lowest has the best price.

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The total charge for a taxi ride in NYC includes an initial fee of $3.75 plus $1.25 for every 1/2 mile traveled. Jodi took a tax

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1.25 for every half mile.....this means it is 2.50 for every mile

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3 years ago

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Consider the following figure:

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The solid 3D object that is produced by rotating the triangle about line m is a cone.

<h3>What is a triangle?</h3>

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2 years ago

What is the equation for 5x=25?

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3 years ago

A stack of cards consists of seven red and four blue cards. A second stack of cards consists of eleven red cards. A stack is sel

Ann [662]

Answer:

0.1733 = 17.33% probability the first stack was selected.

Step-by-step explanation:

To solve this question, it is needed to understand conditional probability, and the hypergeometric distribution.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Conditional probability:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

Probability of all red cards for the first stack:

For this, we use the hypergeometric distribution, as the cards all chosen without replacement.

7 + 4 = 11 cards, which means that $N = 11$ .

7 red, which means that $k = 7$

3 are chosen, which means that $n = 3$

We want all red, so we find P(X = 3).

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 3) = h(3,11,3,7) = \frac{C_{7,3}*C_{4,0}}{C_{11,3}} = 0.2121$

Conditional probability:

Event A: All red

Event B: From the first stack.

Probability of all red cards:

0.2121 of 50%(first stack)

1 of 50%(second stack). So

$P(A) = 0.2121*0.5 + 1*0.5 = 0.60605$

Probability of all red cards and from the first stack:

0.21 of 0.5. So

$P(A \cap B) = 0.21*0.5 = 0.105$

What is the probability the first stack was selected?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.105}{0.60605} = 0.1733$

0.1733 = 17.33% probability the first stack was selected.

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3 years ago