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Schach [20]
3 years ago
8

A researcher records the following scores on a working memory quiz for two samples. Which sample has a larger standard deviation

? Sample A: 2, 3, 4, 5, 6, 7, and 8 Sample B: 4, 5, 6, 7, 8, 9, and 10
Mathematics
1 answer:
Natalka [10]3 years ago
4 0

Answer:

Standard deviations of both sets are equal

Step-by-step explanation:

We calculate the standard deviations for each sample set

For A

We calculate mean = (2+3+4+5+6+7+8)/7 = 35/5 = 7

We calculate deviations from the mean I.e each element in data set minus mean

x (x-mean)

2 -3

3. -2

4. -1

5. 0

6. 1

7 2

8. 3

If we look closely, we see that the sum of deviations is 0 , hence our standard deviation would be value zero too. This means there is no deviation about the mean

For the second set too, we calculate the mean = 4+5+6+7+8+9+10 = 49/7 = 7

We calculate the deviations too

X. X-mean

4. -3

5 -2

6 -1

7 0

8. 1

9 2

10. 3

Adding sum of deviations, we can see that the S.D is zero here too

Hence, the S.D of both data sets are equal

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yaroslaw [1]

The cost of meal = $30

The tip to the waiter = 8%%

Discount = 10%%

Cost = 30 + 0.08 * 30 - 0.1 * 30

Cost = 30(1 + 0.08 - 0.1)

Cost = $$29.40

8 0
2 years ago
For the month of November in a certain​ city, 88​% of the days are cloudy. Also in the month of November in the same​ city, 54​%
Gnoma [55]

Answer:

There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.

Step-by-step explanation:

We have these following probabilities:

An 88% probability that the day is cloudy.

An 54% probability that the day is both foggy and cloudy.

What is the probability that a randomly selected day in November will be foggy if it is cloudy​?

This is the percentage of days that are cloudy and foggy divided by those that are cloudy. So:

P = \frac{0.54}{0.88} = 0.6136

There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.

4 0
3 years ago
One leg of a right triangle has a length of 5m. The other sides have lengths that are consecutive integers. Find these lengths.
pickupchik [31]

The lengths of the other two sides of the right triangle are 12 and 13

<h3>Pythagorean theorem </h3>

From the question, we are to determine the lengths of the other sides of the triangle

From the given information,

The other sides have lengths that are consecutive integers

Thus,

If the length of the other side is x

Then,

The hypotenuse will be x + 1

By the <em>Pythagorean theorem</em>, we can write that

(x+1)² = x² + 5²

(x+1)(x+1) = x² + 25

x² + x + x + 1 = x² + 25

x² - x² + x + x = 25 - 1

2x = 24

x = 24/2

x = 12

∴ The other leg of the right triangle is 12

Hypotenuse = x + 1 = 12 + 1 = 13

Hence, the lengths of the other two sides are 12 and 13

Learn more on Pythagorean theorem here: brainly.com/question/4584452

#SPJ1

7 0
2 years ago
Please Help !!!
Rina8888 [55]

Answer:

40

Step-by-step explanation:

Sums:

1, 3

2, 2

4, 0

31 and 22 are to small of numbers.  That leaves 40.

40 and 04

so 40

  - 04

____

=  36

Good luck,

Camryn :)

7 0
3 years ago
A marketing representative wants to estimate the proportion of people in a state who like the new design on the packaging of a c
Effectus [21]

Answer:

The correct option is;

(B) Yes, because sampling distributions of population proportions are modeled with a normal model.

Step-by-step explanation:

Here we have the condition for normality being that where we have a population with a given mean and standard deviation, while a sufficiently large sample is drawn from the population while being replaced, the distribution of the sample mean p will be distributed normally according to central limit theorem.

8 0
3 years ago
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