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Slav-nsk [51]
3 years ago
14

Alright, this a Honors Geometry question:

Mathematics
1 answer:
Natalka [10]3 years ago
8 0
The image will reflect and there is your answer

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I need help ASAP<br><br> Please and thanks
Leokris [45]

Answer:its number 3

Step-by-step explanation:

3 0
3 years ago
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Write the name of the period that has the digits 913 in 913256
solniwko [45]
I don't understand what your asking
8 0
3 years ago
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Your medical research team is investigating the standard deviation of the cost of a 30-day-supply of a certain heart medication.
Valentin [98]

Considering the situation described, the hypothesis tested are given as follows:

  • The null hypothesis is H_0: \sigma \geq 23
  • The alternative hypothesis is H_1: \sigma < 23

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if the standard deviation is not less than $23, that is:

H_0: \sigma \geq 23

At the alternative hypothesis, it is tested if there is significant evidence t conclude that the standard deviation is less than $23, that is:

H_1: \sigma < 23

More can be learned about an hypothesis test at brainly.com/question/26454209

4 0
2 years ago
Can someone plz help me with this
Levart [38]
D.
None of the above. Because your expression would be, 2 + 0.75 x 6.
Hope it helps. ;)
7 0
3 years ago
A highway map of Ohio has a coordinate grid superimposed on top of the state. Springfield is at point (1, –4) and Columbus is at
Vedmedyk [2.9K]
The midpoint, where the rest area is, will just be the average of the coordinates of Springfield and Columbus.

Rest Area=((1+7)/2, (-4+1)/2)

Rest Area=(4, -1.5)

The distance between the two cities can be found using the Pythagorean Theorem, which used in the manner is often referred to as the "distance" formula between two points.

d^2=(x2-x1)^2+(y2-y1)

d^2=(7-1)^2+(1--4)^2

d^2=36+25

d^2=61

d=√61  and we are told that each unit is equal to 5.38mi so the distance from Springfield to Columbus is:

D=5.38√61 mi

D≈42.02mi  (to nearest hundredth of a mile)
3 0
3 years ago
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