1. you can use the multiplication sign X
2. you can use a write it as 12X
3. you can use parentheses (3)X
option A.55°
Answer:
Solution given:
<x+<y=<z
exterior angle of a triangle is equal to the sum of two opposite interior angle
4n-18+n+8=133-6n
5n+6n=133+10
11n=143
n=143/11
n=13
<u>exterior</u><u> </u><u>angle</u><u> </u><u>=</u><u>1</u><u>3</u><u>3</u><u>-</u><u>6</u><u>*</u><u>1</u><u>3</u><u>=</u><u>5</u><u>5</u><u>°</u>
<u>option</u><u> </u><u>A</u><u>.</u><u>5</u><u>5</u><u>°</u>
The number can be written as a riot of two decimal numbers e.g 3/10
A(b-c)=d
We are trying to leave c on one side, so we have to divide by a on both sides first to get
b-c=d/a
now we can subtract by b on both sides to get
-c=d/a-b
now multiply both sides by -1 to get
<span>c=-d/a+b</span>
Answer:
tan x = opp / adj = -3/4
Step-by-step explanation:
If sin x = -3/5, then we have the following info as a starting point:
opposite side = -3 (implying that the angle is in either QIII or QIV), and
hypotenuse = 5.
Using the Pythagorean Theorem, we find that x² + (-3)² = 5², where x is the length of the adjacent side. Solving for x², we get x² = 25-9 = 16, so that the adj. side, x, is either +4 or -4.
If cos x > 0, then x must be in either QI or QIV.
If both conditions are satisfied (sin x = -3/5 and cos x > 0), then the angle x must be in QIV.
Then tan x = opp / adj = -3/4.
