The box has volume
11 in × 3 in × <em>x</em> in = 33<em>x</em> in³
and surface area
2 (11 in × 3 in + 11 in × <em>x</em> in + 3 in × <em>x</em> in) = (66 + 28<em>x</em>) in²
The volume and area have the same value if
33<em>x</em> = 66 + 28<em>x</em>
Solve this equation for <em>x</em> :
33<em>x</em> - 28<em>x</em> = 66
5<em>x</em> = 66
<em>x</em> = 66/5 = 13.2
Answer:
Distance between -23 & 17 = 40
Step-by-step explanation:
Answer:
<h2>25 1/6 square yards</h2>
Step-by-step explanation:
I am assuming you mean the area of the shaded figure.
So, let's do it this way.
Let's subtract the total area from the unshaded area:
7 1/4 x 6 = 43 1/2
Area of non-shaded = 18 1/3
Area of shaded = 43 1/2 - 18 1/3 = 25 1/6
<em>Hope that helps! :)</em>
<em></em>
<em>-Aphrodite</em>
Answer:
Step-by-step explanation:
I always like to use the mean if I can. In this data set, it's probably not a very good idea. Too much weight is given to that 7.2 and the two 3.2s.
I would choose the median, because the mode is the same answer and that's a good enough reason for choosing anything. 2 out 3 isn't bad as they say in Baseball.
0.0048 Decimal
3/ 625 Fraction
