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Lady_Fox [76]
3 years ago
9

After a system is released and the user base grows, the demands on the development and support team will ______.

Computers and Technology
1 answer:
otez555 [7]3 years ago
6 0

After a system is released and the user base grows, the demands on the development and support team will increase.

The development team can scale vertically by adding new people to the team.

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The answer is "Option C".

Explanation:

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Explanation:

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Write a program that accepts 5 number and arrange them in ascending order​
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3 years ago
The return value is a one-dimensional array that contains two elements. These two elements indicate the rows and column indices
erma4kov [3.2K]

Answer:

In Java:

import java.util.Scanner;  

import java.util.Arrays;  

public class Main  {  

public static void main(String args[])  {  

Scanner input = new Scanner(System.in);

int row, col;  

System.out.print("Rows: ");    row = input.nextInt();

System.out.print("Cols: ");     col = input.nextInt();  

int[][] Array2D = new int[row][col];

System.out.print("Enter array elements: ");

for(int i =0;i<row;i++){    

    for(int j =0;j<col;j++){

        Array2D[i][j] = input.nextInt();  

    }     }

 

int[] maxarray = findmax(Array2D,row,col);

System.out.println("Row: "+(maxarray[0]+1));

System.out.println("Column: "+(maxarray[1]+1));

}  

public static int[] findmax(int[][] Array2D,int row, int col)   {  

int max = Array2D[0][0];

int []maxitem = new int [2];

for(int i =0;i<row;i++){

    for(int j =0;j<col;j++){

        if(Array2D[i][j] > max){  

            maxitem[0] = i;

            maxitem[1] = j; } }    }

 

return maxitem;  

}  

}

Explanation:

The next two lines import the scanner and array libraries

<em>import java.util.Scanner;   </em>

<em>import java.util.Arrays;   </em>

The class of the program

<em>public class Main  {  </em>

The main method begins here

<em>public static void main(String args[])  {  </em>

The scanner function is called in the program

<em>Scanner input = new Scanner(System.in);</em>

This declares the array row and column

int row, col;

This next instructions prompt the user for rows and get the row input  

System.out.print("Rows: ");    row = input.nextInt();

This next instructions prompt the user for columns and get the column input  

System.out.print("Cols: ");     col = input.nextInt();  

This declares the 2D array

int[][] Array2D = new int[row][col];

This prompts the user for array elements

System.out.print("Enter array elements: ");

The following iteration populates the 2D array

<em> for(int i =0;i<row;i++){    </em>

<em>     for(int j =0;j<col;j++){ </em>

<em>         Array2D[i][j] = input.nextInt();   </em>

<em>     }     } </em>

This calls the findmax function. The returned array of the function is saved in maxarray  

int[] maxarray = findmax(Array2D,row,col);

This prints the row position

System.out.println("Row: "+(maxarray[0]+1));

This prints the column position

System.out.println("Column: "+(maxarray[1]+1));

The main method ends here

}  

The findmax function begins here

public static int[] findmax(int[][] Array2D,int row, int col)   {  

This initializes the maximum to the first element of the array

int max = Array2D[0][0];

This declares maxitem. The array gets the position of the maximum element

int []maxitem = new int [2];

The following iteration gets the position of the maximum element

<em>for(int i =0;i<row;i++){ </em>

<em>     for(int j =0;j<col;j++){ </em>

<em>         if(Array2D[i][j] > max){  </em>

<em>             maxitem[0] = i; </em><em>-- The row position is saved in index 0</em><em> </em>

<em>             maxitem[1] = j;  </em><em>-- The column position is saved in index 1</em><em>} }    } </em>

This returns the 1 d array

return maxitem;  

}  

7 0
3 years ago
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