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3 years ago

After a system is released and the user base grows, the demands on the development and support team will ______.

Computers and Technology

1 answer:

otez555 [7]3 years ago

6 0

After a system is released and the user base grows, the demands on the development and support team will increase.

The development team can scale vertically by adding new people to the team.

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"In a web app, where is data usually stored? A. Mobile network B. Application storage C. Local computer D. Cloud storage"

ollegr [7]

Answer:

The answer is "Option C".

Explanation:

The local computer also refers to locally, it is a device, that is used by LAN. It is also called as a remote computer, in which all the data is stored in the main computer and accessible by protected password, and certain choices were wrong, which can be described as follows:

In option A, It is used in digital communication.
In option B, It is used in androids.
In option D, It is used to provides web services.

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3 years ago

Universal containers wants to rollout new product bundles with several pricing options. Pricing options include product-price bu

ololo11 [35]

Answer:

a) Custom AppExchange-app for product-pricing

Explanation:

We can find a solution in AppExchange for this product-pricing, surfing in the option, we could get solutions like BoonPlus, and easy pricing Opportunity, this App has a free trial.

With this option is easy to choose a book price, add new products, select pricing rule, we can get an order's product, and calculate pricing, just we must download the app and install it.

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3 years ago

Use the drop-down menus to complete the statements about using column breaks in word 2016

Naily [24]

Answer: Breaks in the word 2016 what do you mean

Explanation:

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3 years ago

Read 2 more answers

Write a program that accepts 5 number and arrange them in ascending order

Schach [20]

5
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7 0

3 years ago

The return value is a one-dimensional array that contains two elements. These two elements indicate the rows and column indices

erma4kov [3.2K]

Answer:

In Java:

import java.util.Scanner;

import java.util.Arrays;

public class Main {

public static void main(String args[]) {

Scanner input = new Scanner(System.in);

int row, col;

System.out.print("Rows: "); row = input.nextInt();

System.out.print("Cols: "); col = input.nextInt();

int[][] Array2D = new int[row][col];

System.out.print("Enter array elements: ");

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

Array2D[i][j] = input.nextInt();

} }

int[] maxarray = findmax(Array2D,row,col);

System.out.println("Row: "+(maxarray[0]+1));

System.out.println("Column: "+(maxarray[1]+1));

}

public static int[] findmax(int[][] Array2D,int row, int col) {

int max = Array2D[0][0];

int []maxitem = new int [2];

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

if(Array2D[i][j] > max){

maxitem[0] = i;

maxitem[1] = j; } } }

return maxitem;

}

Explanation:

The next two lines import the scanner and array libraries

import java.util.Scanner;

import java.util.Arrays;

The class of the program

public class Main {

The main method begins here

public static void main(String args[]) {

The scanner function is called in the program

Scanner input = new Scanner(System.in);

This declares the array row and column

int row, col;

This next instructions prompt the user for rows and get the row input

System.out.print("Rows: "); row = input.nextInt();

This next instructions prompt the user for columns and get the column input

System.out.print("Cols: "); col = input.nextInt();

This declares the 2D array

int[][] Array2D = new int[row][col];

This prompts the user for array elements

System.out.print("Enter array elements: ");

The following iteration populates the 2D array

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

Array2D[i][j] = input.nextInt();

} }

This calls the findmax function. The returned array of the function is saved in maxarray

int[] maxarray = findmax(Array2D,row,col);

This prints the row position

System.out.println("Row: "+(maxarray[0]+1));

This prints the column position

System.out.println("Column: "+(maxarray[1]+1));

The main method ends here

}

The findmax function begins here

public static int[] findmax(int[][] Array2D,int row, int col) {

This initializes the maximum to the first element of the array

int max = Array2D[0][0];

This declares maxitem. The array gets the position of the maximum element

int []maxitem = new int [2];

The following iteration gets the position of the maximum element

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

if(Array2D[i][j] > max){

maxitem[0] = i; -- The row position is saved in index 0

maxitem[1] = j; -- The column position is saved in index 1} } }

This returns the 1 d array

return maxitem;

}

7 0

3 years ago