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Digiron [165]
4 years ago
7

Product of 9/10 times 1/2

Mathematics
1 answer:
oksano4ka [1.4K]4 years ago
3 0

The product of nine tenths times one half is 0.45, or in fraction form, 9/20.

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How do I solve this problem?
Ivan
Cross multiply and turn the mixed number into a fraction
6 0
3 years ago
Find f(x) and g(x) so the function can be expressed as y = f(g(x)) y = Seven divided by x squared. + 10
Damm [24]
F(x) = 7/x
g(x)=x²+10

Then f(g(x))= 7/(x²+10)

By the way    g(f(x))=(7/x)² + 10
 
6 0
3 years ago
Read 2 more answers
I have this math problem that I need to do, can you explain it to me please? Divide 28 cans of soda into two groups so the ratio
Readme [11.4K]

Answer:

12 and 16

Step-by-step explanation:

The ratio between the groups is 3:4, so the fractions are 3/7 and 4/7.

3/7 (28) = 12

4/7 (28) = 16

Check your answer: 12 + 16 = 28, and 12/16 = 3/4.

7 0
4 years ago
Kayla had a balance of $65 in her savings account before withdrawing $28. What is her new balance?
Goshia [24]

Answer: $37

Step-by-step explanation:

6 0
3 years ago
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There are five sales associates at Mid-Motors Ford. The five associates and the number of cars they sold last week are: Sales As
Levart [38]

Answer:

a) There are 10 different samples of size 2.

b) See the explanation section

c) See the explanation section

Step-by-step explanation:

a) We need to select a sample of size 2 from the given population of size 5. We use combination to get the number of difference sample.

\{ {{5} \atop {2}} \} = \frac{5!}{2!(5-2)!} \\= \frac{5!}{2!3!} \\= \frac{120}{2*6} \\= \frac{120}{12} \\=10

b) Possible sample of size 2:

Peter Hankish 8 Connie Stallter 6 Juan Lopez 4 Ted Barnes 10 Peggy Chu 6

  1. Peter Hankish and Connie Stallter ( Mean = (8 + 6)/2 = 14/2 = 7)
  2. Peter Hankish and Juan Lopez (Mean = (8 + 4)/2 = 12/2 = 6)
  3. Peter Hankish and Ted Barnes (Mean = (8 + 10)/2 = 18/2 = 9)
  4. Peter Hankish and Peggy Chu (Mean = (8 + 6)/2 = 14/2 = 7)
  5. Connie Stallter and Juan Lopez (Mean = (6 + 4)/2 = 10/2 = 5)
  6. Connie Stallter and Ted Barnes (Mean = (6 + 10)/2 = 16/2 = 8)
  7. Connie Stallter and PeggyChu (Mean = (6 + 6)/2 = 12/2 = 6)
  8. Juan Lopez and Ted Barnes (Mean = (4 + 10)/2 = 14/2 = 7)
  9. Juan Lopez and Peggy Chu (Mean = (4 + 6)/2 = 10/2 = 5)
  10. Ted Barnes and Peggy Chu (Mean = (10 + 6)/2 = 16/2 = 8)

c) The mean of the population is:

mean = \frac{(8+6+4+10+6)}{5} \\= \frac{34}{5} \\= 6.8

Comparing the mean of the population and the sample; we can say that most of the 2-size sample have their mean higher than that of the population sample. And the variation with the mean is not much. Some sample have their mean greater than population mean, while some sample have their mean greater than the population mean.

4 0
3 years ago
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