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lions [1.4K]
3 years ago
9

Pinnacle Corp. budgeted $700,000 of overhead cost for the current year. Actual overhead costs for the year were $650,000. Pinnac

le's plantwide allocation base, machine hours, was budgeted at 100,000 hours. Actual machine hours were 80,000. A total of 100,000 units was budgeted to be produced and 98,000 units were actually produced. Pinnacle's plantwide factory overhead rate for the current year is?
Mathematics
1 answer:
photoshop1234 [79]3 years ago
7 0

Answer:

Overhead Rate for current year=$7 per machine hour

Step-by-step explanation:

Overhead Cost=$700000

Machine Hours Budgeted=100000

In order to calculate the Pinnacle's factory overhead rate for the current year we will consider the following formula:

Overhead rate for the current year=Budgeted overhead cost for the current year/Machne hours budgeted

Overhead rate for the current year=\frac{700000}{100000}

Overhead Rate for current year=$7

So Pinnacle plantwide factory overhead rate for the current year is $7 per machine hour.

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$38.40

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3 years ago
Two towns are 80km apart. Sylvia wants to drive from one town to the other in exactly one hour. For the first 30minutes she driv
Varvara68 [4.7K]

Answer:

100 km/hr

Step-by-step explanation:

First Leg:

Speed = 60 km/h

Time = 30 min = 0.5 h

1st leg distance = speed x time = 60 km/hr x 0.5hr = 30 km

Second Leg:

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speed = distance / time = 50 / 0.5 = 100 km/hr

5 0
3 years ago
Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1
belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given  x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

            F(x) = \int\limits^a_b {f(x)} \, dx

By using integration formula

\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c

Given  x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

 \int\limits^6_^-6} (x^{5}  + 8 x^{4}  + 2 x^{2}  + 5 x + 15) )dx

<em>On integration , we get</em>

=   (\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}

F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)

= (\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))

After simplification and cancellation we get

 =  \frac{2 X 8 X (6)^{5} }{5} + \frac{2 X 2 X (6)^3}{3} + 2 X 15 X 6

on calculation , we get

= \frac{124,416}{5} + \frac{864}{3} + 180

On L.C.M  15

= \frac{124,416 X 3 + 864 X 5 + 180 X 15}{15}

= 25 351.2 units²

<u><em>Conclusion</em></u>:-

<em>The area of the region between the graph of the given function and the x-axis = 25,351 units²</em>

6 0
2 years ago
5u + 14 &gt; 64<br><br> Can someone tell me what U is?
ale4655 [162]
5u > 64 - 14
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2 years ago
Read 2 more answers
Please help!!! Will give brainly!! 50 points
lara31 [8.8K]

(x,\ y)\to(x-6,\ y-4)\\\\A(3,\ -5)\to A'(3-6,\ -5-4)\to A'(-3,\ -9)\\\\B(6,\ 2)\to B'(6-6,\ 2-4)\to B'(0,\ -2)\\\\C(2,\ 5)\to C'(2-6,\ 5-4)\to C'(-4,\ 1)

5 0
2 years ago
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