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Nastasia [14]
3 years ago
7

Determine whether each expression is equivalent to (2x^3)2/5

Mathematics
2 answers:
-Dominant- [34]3 years ago
7 0

Answer:

1.Yes

2.No

3.No

4.Yes

5.No

Step-by-step explanation:

UNO [17]3 years ago
3 0

Answer:

Yes

No

No

Yes

No

Step-by-step explanation:

The given expression is \sqrt[5]{(2x^{3})^{2}  }

This can be rewritten as

\sqrt[5]{4x^{6} }

Then an x can be factored out to give you

x\sqrt[5]{4x}

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Vladimir79 [104]

Answer: e) 6

Step-by-step explanation:

Let x be mother + children = 18

Father's age = 38

Average age of the family = 14

38 + 18x /( x + 1 )= 14

Opening the bracket

38 + 18x = 14x + 14

Collecting like terms

24 = 4x

x = 6

no of children in the family is 6.

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The intersection of roads M and N creates a 41.4 degree angle. What are the complimentary and supplementary angles of this inter
astra-53 [7]
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5 0
3 years ago
What is 2/3÷6 over five
malfutka [58]
5/9 (fraction simplified)
7 0
3 years ago
A researcher collects data on the relationship between the amount of daily exercise an individual gets and the percent body fat
fredd [130]

Answer: approximately 24

Step-by-step explanation:

We need to plot a regression line.

So we fit a model using the regression of Y on X, that an equation that predict Y for a given X using:

(Y -mean(Y ))= a(X-meanX)...........1

Where the formular of a is given the attachment.

N= the of individuals = 5

Y = amount of fat

X = time of exercise

mean(X )= sum of all X /N

= 131/5 = 26.2

mean(Y) = sum of all Y/N

= 104/5 = 20.8

a = N(SXY) - (SX)(SY)/ NS(X²) -(SX)²......2

SXY = Sum of Product X and Y

SX= sum of all X

SY = Sum of all Y

S(X²)= sum of all X²

(SX) = square of sum of X

a = -0.478

Hence we substitute into 1

Y-20.8 = -0.478 (X-26.2)

Y -20.8 = -0.478X - 12.524

Y = -0.478X + 33.324 or

Y = 33.324 - 0.478X (model)

When X = 20

Y = 33.324 - 0.478 × 20

Y = 33.324 - 9.56

Y = 23. 764

Y =24(approximately)

Carefully meaning of formula used in attachment to the solution they are the same.

4 0
3 years ago
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