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Veronika [31]
4 years ago
13

permutations 2.4 statistics answers A clothing store has a certain shirt in 4 sizes: small, medium, large, and extra large. If i

t has 2 small, 3 medium, 6 large, and 2 extra large in stock, in how many orders can it sell all the shirts?
Mathematics
1 answer:
arsen [322]4 years ago
6 0

Answer: 360,360

Step-by-step explanation:

The number of permutations of n things of which a are identical, b are identical and so on... :-

\dfrac{n!}{a!\ b!....}

Given :  A clothing store has a certain shirt in 4 sizes: small, medium, large, and extra large.

If it has 2 small, 3 medium, 6 large, and 2 extra large in stock, then total shirts : 2+3+6+2=13

Then, the number of orders in which the store can sell all the t-shirts will be :_

\dfrac{13!}{2!3!6!2!}\\\\=\dfrac{13\times12\times11\times10\times9\times8\times7\times6!}{2\times3\times2\times6!\times2}\\\\=360360

Hence, the number of orders in which the store can sell all the t-shirts  = 360,360

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Answer:

The range in which at least 88.89% of the data will lie is (162,318).

Step-by-step explanation:

Given:

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We have to find the range in which at least 88.89% of the data will lie by using Chebyshev's theorem :

Formula :

Lower range = \bar x-ks

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We know that the percentage of the data that lies within 'k' standard deviation is at least,1-1/k^2 and k > 1.

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⇒ 0.1111=\frac{1}{k^2}

⇒ \frac{1}{0.1111} =k^2

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⇒ 240-78,240+78

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The range in which at least 88.89% of the data will lie is (162,318).

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